If it's due to the force of Earth's gravity,no. That would be D= 5(t^2). because s = 1/2a(t^2) ,that is displacement (or distance from origin) = acceleration x time if the object is starting from rest.
Acceleration due to Earth's gravity = approx 10 ms^(-2) and the D= 5(t^2) comes from the formula for displacement which is
s = ut + 1/2 a(t^2) . If u,which is the initial velocity,is zero,you get this expression,which is for an object in free fall in earth's gravity,starting from rest and ignoring air resistance.
For more on this,google SUVAT equations.