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Just use the calculator!   Here is the calc answer:

1.06^30 = 5.7434911729132501

Thanks, guest....

Look under your first post!.

it might be 3, but since you never know it might also be 2 crosses, and a leftover... who cares ?

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http://usefulwebtool.com/en/math-keyboard.php

You can get many symbols here : http://math.typeit.org/

5x^6(2x^3 - 7x^2 + x) = 10 x^9 - 35 x^8 + 5 x^7

You should go to your local Library and look up books on "Essays writing", such as:"The Sacred Beetle and other Great Essays in Science" edited by Martin Gardner and published by Meridian. Also, look up ANY books written by Carl Sagan and Stephen Jay Gould. Carl Sagan's book" Shadows of Forgotten Ancestors" is excellent for the prose in it. Good luck to you.

Answer is easy just say ..............................Whats 9+10 ANSWER 21 LOLOLOLOLOLOLOLOLOL

4(7n²+7n−1)=28n²+28n-4

log₂ 256  - log₅ 625  = 

log 256 / log 2  - log 625/log 5  =

8  - 4    =

4

Marie works at a toy store, and makes different amounts of money depending oon what is purchased.

1 toy box set of wooden blocks costs $5,

1 doll house costs $16.99,

2 books costs $3.69,

1 toy box set of dollhouse accessories is $8.50, and a box set of

5 suffed animals is $13.99.

The tax is 20%.

If Marie sold 15 dollhouses, 12 dollhouse accessory sets, 7 wooden block sets, 29 books, and 20 stuffed animal sets, how much did she make, if you include tax?

\(\begin{array}{|rcll|} \hline && 1.2\cdot ( 15 \cdot $16.99 + 12 \cdot $8.50 + 7 \cdot $5 +29 \cdot \frac{$3.69}{2} +20 \cdot \frac{$13.99}{5} ) \\ &=& 1.2\cdot $501.315 \\ &=& $601.578 \\ \hline \end{array} \)

She makes $601.578 include tax.

What is the sum to this question:
A hiker walked 3 1/6 miles yesterday and 2 1/2 miles today.

\(\begin{array}{|rcll|} \hline && 3 \frac{1}{6} \ \text{miles}+ 2 \frac{1}{2}\ \text{miles} \\ &=& 3+2 +\frac{1}{6} + \frac{1}{2} \\ &=& 5 +\frac{1}{6} + \frac{1}{2} \\ &=& 5 +\frac{1}{6} + \frac{1}{2}\cdot \frac{3}{3} \\ &=& 5 +\frac{1}{6} + \frac{3}{6} \\ &=& 5 +\frac{4}{6} \\ &=& 5 +\frac{2}{3} \\ &=& 5 \frac{2}{3}\ \text{miles} \\ &=& 5.\bar{6}\ \text{miles} \\ \hline \end{array}\)

18/4 divided by 16/17

\(\begin{array}{|rcll|} \hline && \dfrac{ \frac{18}{4} } { \frac{16}{17} } \\\\ &=& \dfrac{ \frac{9}{2} } { \frac{16}{17} } \\\\ &=& \frac{9}{2} \cdot \frac{17}{16} \\\\ &=& \frac{9\cdot 17}{2\cdot 16} \\\\ &=& \frac{153}{32} \\\\ &=& 4\frac{25}{32} \\\\ &=& 4.78125 \\ \hline \end{array} \)

At what time, t, does the object hit the ground? s(t)=t^2−4t−12

\(\begin{array}{|rcll|} \hline s(t) =t^2-4t-12 &=& 0 \\ t^2-4t-12 &=& 0 \\ (t-6)(t+2) &=& 0 \\\\ t = 6 &\text{or}& t = -2 \quad (\text{no solution, because t < 0})\\ \hline \end{array} \)

At time t = 6 the object does hit the ground.

What is 9/16-1/2

\(\begin{array}{|rcll|} \hline && \frac{9}{16}-\frac{1}{2} \\ &=& \frac{9}{16}-\frac{1}{2} \cdot \frac{8}{8} \\ &=& \frac{9}{16}-\frac{8}{16} \\ &=& \frac{9-8}{16} \\ &=& \frac{1}{16} \\ \hline \end{array} \)

Kevin computes that if x is now the number of shares the client holds in her account, then the number of years y that the client has had the account is given by the function y space equals space square root of x minus 10 end root. what is the domain and range?

\(\begin{array}{|llcll|} \hline & y = \sqrt{x-10} \\\\ \text{Domain} & \{x \in \mathbb{R}:x\ge 10 \} \\ \text{Range} & \{y \in \mathbb{R}:y\ge 0 \} \\ \hline \end{array} \)

What is the formula for surface area of a cone?

The surface area of the cone equals the area of the circle plus the area of the cone and the final formula is given by:

\(\text{Surface Area} = \pi r^2 + \pi rl\)

1324/43 = 30.7906976744

Cash me ousside, how bou dah

whats the perimeter of a rhombus of height of 4.55 and a base of 5.2

without mistake:

\(\begin{array}{|rcll|} \hline a^2 &=& \left(\dfrac{5.2}{2}\right)^2 +\left(\dfrac{4.55}{2}\right)^2 \\ a &= & \sqrt{2.6^2+2.275^2} \\ &= & \sqrt{6.76+5.175625} \\ &= & \sqrt{11.935625} \\ &= & 3.45479738914 \\\\ \text{Perimeter} &=& 4\cdot a \\ &=& 4\cdot 3.45479738914 \\ &=& 13.8191895566 \\ \hline \end{array}\)

​whats the perimeter of a rhombus of height of 4.55 and a base of 5.2 ?

\(\begin{array}{|rcll|} \hline a^2 &=& \left(\dfrac{5.2}{2}\right)^2 +\left(\dfrac{4.55}{2}\right)^2 \\ &= & \sqrt{2.6^2+2.275^2} \\ &= & \sqrt{6.76+5.175625} \\ &= & \sqrt{11.935625} \\ &= & 3.45479738914 \\\\ \text{Perimeter} &=& 4\cdot a \\ &=& 13.8191895566 \\ \hline \end{array}\)