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I do believe that's 64.

circumference is 2 times pi times the radius of the circle

 In ordinary arithmetic, the expression has no meaning, as there is no number which, multiplied by 0, gives a (assuming a≠0), and so division by zero is undefined. Since any number multiplied by zero is zero, the expression 0/0 also has no defined value; when it is the form of a limit, it is an indeterminate form. the answer is undefined. zero is incorrect.

LOL this is only some of them and yes it took me a lot longer than I expected to put that altogether :)

The quadrilateral ABCD, where A is (4,5) and C (3,-2) is a square. Find the coordinates of B and D.

\(\text{Let}\ \vec{A} = \binom{4}{5}\\ \text{Let}\ \vec{C} = \binom{3}{-2} \)

\(\vec{O}\) is the midpoint of \(\vec{A}\) and \(\vec{C}\)

\(\begin{array}{|rcll|} \hline \vec{AC} &=& \vec{A}-\vec{C} = \binom{4}{5}-\binom{3}{-2}=\binom{1}{7} \\ \vec{OC} &=& \frac12\vec{AC} = \frac12\binom{1}{7}=\binom{0.5}{3.5} \\ \vec{OD} &=& \vec{OC}_{\perp} \qquad \vec{OC}_{\perp} = \binom{-3.5}{0.5} \qquad \vec{OC}\cdot\vec{OC}_{\perp} = 0\ \checkmark \\ &=& \binom{-3.5}{0.5} \\ \vec{OB} &=& -\vec{OD}=\binom{3.5}{-0.5} \\ \vec{D} &=& \vec{C}+\vec{OC}+\vec{OD}= \binom{3}{-2}+\binom{0.5}{3.5}+\binom{-3.5}{0.5} \\ &=& \binom{0}{2} \\ \vec{B} &=& \vec{C}+\vec{OC}+\vec{OB}= \binom{3}{-2}+\binom{0.5}{3.5}+\binom{3.5}{-0.5} \\ &=& \binom{7}{1} \\ \hline \end{array} \)

Wow Melody! Your fingers must be tired from typing that! That is a really long list! I thought you would have had 5 or 6 not 35! Lol! :)

Arctan x   means 'the angle whose tangent is x'      As does arcsinx means 'the angle whose sine is x'.    When you see arctan,arcsin,arccos,  you are looking at expressions for angles.    -    Here's a handy thing to know: --

If you know that arctan x = 1/2 ,for example,you can draw the right-angled triangle with opposite side length 1,adjacent side 2  and find all sides and angles.  As you can if you were given similar expressions for arcsin etc.

We genetically enhanced chimps are partial to roasted vole. 

x + x   = 2x

Unless it's Roman Numerals.......then....

X + X   =    XX   =     20

Or....beer......then.....it's Dos Equis

(6x7)+(?-6)=60      simplify

42 + ( ? - 6)   = 60     subtract  42 from each side

? - 6   =   18        add 6 to both sides

?     =   24

Hey.....so does Melody......particularly if it's beef.......!!!!!

Maybe not the fastest [or easiest ] way to do this....but

The midpoint of ( 4,5)  and ( 3, -2) is  (3.5, 1.5)

And we can let A and C  be the endpoints of a diameter of a circle that has its center at (3.5, 1.5)......and the radius^2  = (4 -3.5)^2 + (5 - 1.5)^2  = 12.5

So.....the equation of this circle will be  (x - 3.5)^2 + (y - 1.5)^2  = 12.5

And the slope of the line joining AC  = 7.........a perpedicular line to this passing through (3.5,1.5) will have a slope  = (-1/7)...

So the equation of this line  is  y = (-1/7)(x - 3.5) + 1.5

And "B" and "D" will lie on the intersection of this line and the  circle

Sub this linear equation into  the equation of the circle for y  and we have

(x - 3.5)^2 + [ ( -1/7)(x - 3.5) + 1.5 - 1.5]^2  = 12.5

(x - 3.5)^2 + ( -x/7 + .5)^2  = 12.5

x^2 - 7x + 12.25 + x^2/49 - x/7 + .25  =  12.5

x^2 - 7x + x^2/49 - (1/7)x   = 0

49x^2 - 343x + x^2 - 7x  = 0

50x^2 - 350x = 0

x^2 - 7x  =  0   factor

x(x - 7)  = 0      so x = 0  and x = 7

And the associated y coordinates are 

y = (-1/7) (0 - 3.5) + 1.5  =  2     and

y = (-1/7) (7 - 3.5) + 1.5   =   1

So....  "B"   = ( 7, 1)    and "D"   = (0, 2)

Here's a pic :

420

same

Thank you Sir Alan. Lancelot would throw banana peels at me for that.  

\(v = \sqrt{\dfrac{362.07}{53}*2.6} = 4.21 m/s \hspace{1em} \Leftarrow \text {Solution -- }\textcolor {red} {(Corrected \;work \;product \;for \;solution.)}\\ \)

Yes i guess so but the question is very poorly written. ://

yes

Example Wolfram Alpha: