sqrt (101) will be irrational.....this will happen anytime we have some quantity left under a root
\(\large{\sqrt[3]{\frac{-8}{27}}=\frac{\sqrt[3]{-8}}{\sqrt[3]{27}}=\frac{-2}{3}}\)
432/22 = 19.636
252/22 = 11.454
Thus.....[ (1//22)x, (1/22)y ] is incorrect
Instead.....
432/24 = 18
252/14 = 18
The correct scaling is [ (1/18)x, (1/18)y ]
6x^3+17x^2+10x-3 / 2x+3
3x^2 + 4x - 1
2x + 3 [ 6x^3 + 17x^2 + 10x - 3 ]
6x^3 + 9x^2
-----------------------------------------------
8x^2 + 10x
8x^2 + 12x
--------------------------------
-2x - 3
------------------
So.....6x^3+17x^2+10x-3 / 2x+3 = 3x^2 + 4x - 1
Let's talk about kitty kats. BTW, hi!
10...............................
4 sec x +5 = 13
4 sec x = 8
sec x = 2
1/cos x = 2
cos x = 1/2
x = 1.0472 R 5.236 R or 60 degrees and 300 degrees (pi/3 and 5pi/3)
4secx+5=13 subtract 5 from both sides
4secx = 8 divide both sides by 4
secx = 2
If the secx = 2, then cosx = 1/2
And this happens at x = pi/3 and x = 5pi/3
I suppose that you're technically correct......the common difference is -5 [ we are subtracting 5 each time ]
, it's 6.
Is d= -5 or 5?
then if it's 5 shouldn't it be 253+(n-1)*5?
Yay! I'm part of it!
Good idea.....!!!
The last term is 253
And the common difference in terms is 5
So......the 20th term from the last =
253 - 5(n - 1) =
253 - 5(20 - 1) =
253 - 5(19) =
158
Shift+x2
( [.9 + .8 + .7 + .6] - [.4 + .3 + .2 + .1 ] ) * .5 =
(3 - 1 ) * .5 =
2 * . 5 =
1
can we find the answer by reversing the A.P?
That is kind of ambiguous; there are two possible answers.
24 - 1/8 = 23 7/8 or 23.875
24 - (1/8(24)) = 24 - 3 = 21
(0 + 3) (10 + 3) =
(30 + 9)(20 + 3)=
(600 + 180 + 90 + 27) (30 + 3) =
(..............+ 81)(40 + 3)....... etc.
So (3 x 13 x 23 x........183 x 193) / 5 will have a remainder =
3^20 mod 5 =
(3^4)^5 mod 5 =
(3^4) mod 5 =
Take the original amount and multiply by 1 + 10% = 1.1
A slightly ambiguous question
two possible answers
24-1/8 = 23 7/8
24 - 1/8(24) = 21
Common difference between terms is 5 (8-3 = 5 13-8 = 5 etc)
this is of the form 3 + 5 (n-1)
3 + 5n -5 = 5n-2 where n= number of the term
20th term 5(20)-2 = 98
logbase4(15) = x
by definition of logs 15 = 4^x
take log base 10 of both sides
log 15 = log(4^x)
log 15 = x log 4
x = log 15/log 4 = 1.95344 ~ 1.953
Let's see what would happen if we just called the answer zeri, the imaginary number that represents 0 divided by 0. Okay?
a) The length of the secant RT, times its external segment, ST, equals the square of the tangent segment TU.
b) RT * ST = TU^2
9 * 4 = TU^2
36 = TU^2 take the square root of both sides
6 = TU
The answer is 3,696,250,887.
