All Answers 356066 Answers

Don't know whether or not this is the long version, but Melody hasn't posted it so I will

\(\displaystyle \tan2x = -\cot(x+\pi/3),\\\frac{\sin2x}{\cos2x}=-\frac{\cos(x+\pi/3)}{\sin(x+\pi/3)},\\\sin2x\sin(x+\pi/3)=-\cos2x\cos(x+\pi/3),\\ \cos2x\cos(x+\pi/3)+\sin2x\sin(x+\pi/3)=0,\\\cos[2x-(x+\pi/3)]=0,\\\cos(x-\pi/3)=0,\\x-\pi/3=(2n+1)\pi/2=n\pi+\pi/2,\;\;n=0,\pm1,\pm2,\dots\\x=n\pi+5\pi/6,\;\;n=0,\pm1,\pm2,\dots\)

225.000.000+35.000=225.035.000

  4e^x=8   | :4

    e^x=2 

 lne^x=ln2

 x*lne=ln2       (lne=1)

       x=ln2

       x= 0,693147181...

Hi Max,

There’s an omission in your equation.  The Sigma needs squared.

\(\large \sigma^2 =\normalsize \dfrac{1}{N-1}\left(\displaystyle\sum^{N-1}_{i=0}x^{2}_{i}-\dfrac{1}{N}\left(\displaystyle\sum^{N-1}_{i=0}x_i\right)^2\right)\)

Or use the square root of the equation:

\(\large \sigma =\normalsize \sqrt{\dfrac{1}{N-1}\left(\displaystyle\sum^{N-1}_{i=0}x^{2}_{i}-\dfrac{1}{N}\left(\displaystyle\sum^{N-1}_{i=0}x_i\right)^2\right)}\)

This is an efficient computational form of the equivalent:

\(\sigma = \sqrt { \frac{1}{N} \sum \limits_{i=1} ^ {N}(\chi - \mu)^2 }\)

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The formula for circular standard deviation is in post #3

Directional statistics (also circular statistics or spherical statistics) is the subdiscipline of statistics that deals with directions (unit vectors in Rn), axes (lines through the origin in Rn) or rotations in Rn. More generally, directional statistics deals with observations on compact Riemannian manifolds. (https://en.wikipedia.org/wiki/Directional_statistics)

Here are the equations for Circular Standard Deviation (from the same source noted above):

\(S(z)={\sqrt {\ln(1/R^{2})}}={\sqrt {-2\ln(R)}}\small \hspace{25pt} \text {Equation for Sample Circular Standard Deviation } \\ {\overline {S}}(z)={\sqrt {\ln(1/{\overline {R}}^{2})}}={\sqrt {-2\ln({\overline {R}})}} \hspace{24pt} \small \text {Equation for Population Circular Standard Deviation } \\\)

the answer to 2000+905467 is 906567

A=1.6C
B=0.4C
C=D
1.6C + .4C + 2C =4,400 
C=1,100 -What C gets
D=1,100 - What D gets
A=1,760 - What A gets
B=440 - What B gets.

The work can be 1,2 or 3 letters long.

If it is 1 letter then there are 5 choices

If it is 2 letters then there are 5 choices for the first letter and then 5 choices for the second letter. 

   That is 5*5 = 25 posibilities

If it is 3 letters then there are 5 choices for the first letter and then 5 choices for the second letter and 5 for the third

   That is 5*5*5 = 125 posibilities

So that makes

5+25+125 = 155  possible words    

one: \(\sqrt{79}-5x=x-11\)

  or

two: \(\sqrt{79-5x}=x-11\)          ?

Yes, in every right triangle

tan(an angle) = (length of side opposite) / (length of side adjacent)

i think this person wants to spread knowledge and plus, you dont own the website so you really cant do anything about it

I also have run into that page a few times. I was wondering if it was just me too.

f(x) = a(x - h)² + k

h controls shifting left and right. We want to make a - 2 shift.

k controls shifting up and down. We want to make a + 3 shift.

a controls "steepness" basically. We just want normal steepnees of 1.

f(x) = 1(x - -2)² + 3

f(x) = (x + 2)² + 3

This gives a really good idea of what a, h, and k do:

About 1600

lolz

There's an equation to this... l just can't put my finger on it.

G-ghosts?! l won't be on here for a while then! Not even for a Scooby Snack!

Yeah, HSC....I can go to the calculator and it usually reconnects....however....sometimes I have to do this more than once.....apparently.....there are still some "ghosts in the machine"

Sometimes, I get it.

lf you like the quote just leave a thumbs up to show that you actually like this and so l can keep pumping these through. c:

Phill, can you explain a little more, cause i don't understand this question.

5 : 3   means that there are 8 equal  parts of the 104

And the number of cats is (5/8)  of this.....so

(5/8) (104)  =

520 / 8  =

260 / 4  =

130 / 2  =

65  cats