All Answers 358514 Answers

let the larger number =L
The smaller number =S
L + S = 13
2L + 2 =5S , solve for L, S
L = 9
S = 4

-44x +20....

1 million and one

With Poisson distribution, P(x) = e^-mumu^x/x!

Here:  mu = 1.3, x = 4, so P(4) ≈ 0.032

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I know! Death

-3- I like hershey candies.

My favorite KIND of chocolate candy is just dark chocolate. x'D

There is no real answer, as it is equal to infinity. c:

2 googleplex

FV = PV [1 + R]^N

FV = 9,000 [1 + 0.06/12]^(14*12)

FV = 9,000 [1.005]^168

FV = 9,000 x 2.31152383......

FV =$20,803.71 - Balance in the account after 14 years.

The equation is percentage*base price

(.3*60)

R = 4*10^-3V/10^-10A → 4*10⁷ohms

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Use a calculator.

$18            

there is a toggle button on the bottom :)

thanks

How to calculate the median?

Look there purely.

my question

what is after a million?

One million and one.

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I REALLLY NEED HELP

6/7 x 5/11 x 1/3

.                            \(\scriptsize {2}\)

\(\frac{6}{7}\times\frac{5}{11}\times\frac{1}{3}=\frac{[{\color{green}6}]\times5\times1}{7\times11\times[{\color{green}3}]}=\) \(\color{blue}\frac{10}{77}\) 

.                                      \(\scriptsize {1}\)               

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Oh my god!! I have to escape from that!! I can't get caught!!

I vote iSpy as well!

That's what it says as an answer, might be a typo in my book though!

i need help

2z^2-11z-21

As function with zeros is 2z^2-11z-21

\(f(z)=2z^2-11z-21=0\)

\(z = {-b \pm \sqrt{b^2-4ac} \over 2a}\)

\(z = {11 \pm \sqrt{121+1684} \over 4}\)

\(z=\frac{11\pm42.485}{4}\)

\(z_1=13.371\\z_2=-7.871\)

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