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My face after seeing all this.....

You know, I find set notation confusing enough when it does not involve dresses, dates and proms!

Rosala, ot is ver nice of you to loan Beth your dress.  It is a lovely dress.  Beth will look very sophisticated!

Dude when in life would you have to answer this.....

If you were in the nuclear industry, or in astrophysical research, to name a couple, you would have to know this.  You should get out more, your view of life is too narrow!

I don't think anyone undersands your question.

It went right here;

LOL, reinout!!!.....I thought about the second thing, too....I don't think it works, either!!!

Maybe our crystal ball needs some polishing  !!!!

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Thank you.... For that

u r welcome Alan!

$$E = mc^2 \Rightarrow m = \frac{E}{c^2} \mbox{ and } E = \frac{m}{c^2}\\
\mbox{ (Since c = 299 792 458) } m = \frac{5000000}{299792458^2} \mbox{ if e = 5000000 and } E = \frac{5000000}{299792458^2} \mbox{ if m = 5000000}$$

$${\frac{{\mathtt{5\,000\,000}}}{{{\mathtt{299\,792\,458}}}^{{\mathtt{2}}}}} = {\mathtt{0.000\: \!000\: \!000\: \!055\: \!632\: \!5}}$$

Dude when in life would you have to answer this...... But correct, you've answered a trick question

That's nonsense!  c is the velocity of light.

I guess this isn't a serious question!

M and C are both 5 million

I already use it.......I don't find it as intuitive as Desmos, though.....but I suppose it does do some things better

1. Does the 5 million refer to mass or energy?

2. What are its units?

The expression is given by some fixed costs (5 dollars),

and by some costs depending on how many pages there are (2 dollars and 15 cents).

Therefore for one page we have

$$5 + 2.15$$

for two pages we have

$$5 + 2.15 + 2.15$$

and for p pages we have

$$\mbox{ }\mbox{ }\mbox{ }\mbox{ }\mbox{ }\mbox{ }\mbox{ }\mbox{ }\mbox{ }\mbox{ }\mbox{ }\mbox{ }\mbox{ }\mbox{ }\mbox{ }\mbox{ }\mbox{ }\mbox{ }\mbox{ }\mbox{ }p\\
5+\overbrace{2.15+2.15+...+2.15+2.15}$$

or similarly

$$5+2.15p$$

If we evaluate this for 28 pages we have

$${\mathtt{5}}{\mathtt{\,\small\textbf+\,}}{\mathtt{2.15}}{\mathtt{\,\times\,}}{\mathtt{28}} = {\frac{{\mathtt{326}}}{{\mathtt{5}}}} = {\mathtt{65.2}}$$

No Chris I always use GeoGebra for pictures like this.

It is a free download - well worth it.

It is quite powerful but i don't know how to use it very well.  It is not terrible intuitive but with a bit of mucking around you can draw things like this fairly quickly.

You should download it and have a play.

I give you;

No, I'm kidding, but I seriously don't know what they want you to do...

Do they want you to find the values of R

and do you mean [r/7-1] = $$\frac{r}{7}-1$$

or do you mean [r/(7-1)] = $$\frac{r}{7-1}$$

None of these would work....R has to be divisible by 7.

(The answer is 35)

I'll answer if you remove the 5 points you've given yourself 

o ok i thought i was missing out on somekind of code or sumting..