Problem 14:
Given: Chord(AC) and Chord(BD) intersect at E. Arc(AB) is congruent to Arc(CD)
To Prove: Triangle(ABC) is congruent to Triangle(DCB)
The proof can contain the following:
Chord(AB) is congruent to Chord(CD) because they are chords of congruent arcs.
Arc(BC) is congruent to Arc(BC) by identity.
Arc(ABC) is congruent to Arc(DCB) by addition.
Chord(AC) is congruent to Arc(BD) because they are chords of congruent arcs.
Chord(BC) is congruent to Chord(BC) by identity.
Triangle(ABC) is congruent to Triangle(DCB) by SSS.