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no prob that is what friends r for

Thanks deare

The probability of rolling an even number is 1/2

The probability of rolling a 3 is 1/6

Since the probabilities are independent the probability of rolling an even followed by a 3 is just the product of the two, namely (1/2)*1/6) → 1/12

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Awe thanks girl! Same goes to you!🙃

Yeah, it got hit by a car!😔  May it rest in peace 

omg really that is soooo sad

Not sure, but there is a de@d deer on the side of my road 

Help? I don't know how to do this question

Tangent Secant Theorem

$\overline{AD}^2 = \overline{AB} \cdot (\overline{AB} + \overline{BC}) \\ \overline{AD}^2 = 16 \cdot (16 +9) \\ \overline{AD}^2 = 16 \cdot 25 \\ \overline{AD} = 4 \cdot 5 \\ \overline{AD} = 20$

1.56*sin45=1.33sin(theta)

$1.56*sin45=1.33sin(\theta)\\ 1.56*\frac{1}{\sqrt2}=1.33sin(\theta)\\ 1.56*\frac{1}{\sqrt2}\div 1.33=sin(\theta)\\ sin(\theta)=0.829388405\\ \theta=sin^{-1}0.829388405\\ \theta \approx 56^\circ 2'9'' \qquad \text{This is just the first quad answer}\\ \text{Sin is positive in the second quad as well}\\ \theta \approx 180^\circ-56^\circ 2'9''\\ \theta \approx 123^\circ 57'51''\\ so\\ \theta \approx 56^\circ 2'9''+2n\pi \quad or \quad \theta \approx 123^\circ 57'51''+2n\pi \quad where\;\; n\in Z\\ \text{Put that together and you get}\\ \theta =180n+(-1)^n*56^\circ 2'9'' \quad where\;\; n\in Z\\ $

You mean average increase per year. ??

Do you have a question with numbers ??

There are 360 degrees in a circle and the area of a whole circle is  $\pi*r^2$

so

are of a sector is the fraction of the circle that you have.  

 i.e.      $\frac{sector\; angle \; }{360}$

multiplied by the are of the whole circle.

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which is

$\text{Area of sector }=\frac{sector\;angle\;in\;degrees}{360}\times \pi r^2 \qquad units^2$