Given cosx=12/13 and sinx=5/13 . What is ratio for tanx ?
\(cos\ x=\frac{12}{13}\\x=arccos\frac{12}{13}=22.61986°\)
\(sin\ x=\frac{5}{13}\\x=arcsin\frac{5}{13}=22.61986°\)
\({\color{blue}tan\ x= \frac{sin\ x}{cos\ x}=\frac{5\cdot 13}{13\cdot 12}\color{blue}=\frac{5}{12}}\\ x=arctan\frac{5}{12}=22.61986°\)
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