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2/125 → (2*8)/(125*8) → 16/1000 → 0.016

Thanks 

Good...!!!!...two great minds can't possibly be incorrect....can they   ???

LOL!!!!

BTW - I liked that tecnique you used on that  parabola - focus - directrix problem yesterday

I added that one  to  my "tool chest"

Personally, yes. 

Wow, we have the same method xD

Since the interior angle is 29x, and the exterior angle is x, then \(29x+x=180\).

Combine like terms: \(30x=180\)

Divide both sides by 30: \(x=6\).

Now, the exterior angle measures 6˚. We know that the sum of all exterior angles add up to 360˚. So... \(6s=360\), where s is the number of sides.

Divide both sides by 6: \(s=60\).

The polygon has 60 sides. 

The sum of the  interior and exterior angles = 180°

So......this means that

x +  29x = 180

30x  =  180

x =  6°

And the measure of any exterior angle   is given by

360 / N      where N is the number of sides  ..so....

360 / N  =  6      multiply both sides by  N   

360 =  6N       divide both sides by 6

60  = N  = the number of sides

Proof  ....  this "formula"  gives the measire of an interior angle of a regular polygon of N sides

(N - 2) * 180 / N

When N  = 60, we have

(60 - 2) 180 / 60   =   58 * 3  =   174°

So...... 174°  + 6°   =  180°

When dividing, for example, \(a\over b\), we ask the question, "What is x if \(a=bx\)?" For \(0\over0\), this becomes \(0x=0\). Here we have a problem. This has infinitely many solutions! Therefore, 0 divided by 0 is indeterminate.

Got it.....thanks.....!!!!!

  We have that the domain of f(x) is

- 1  < x <  1

Then the domain of  f ( 1/x)  is

-1  <  1/x  <  1    

-1 < 1/x       this will be true when  x < -1  and  x > 0

And

1/x < 1       this will be true when      x > 1

So.....we need to take the most restrictive interval(s)  in our solution

So the domain of  f (1/x)  is    ( - inf, -1)  U ( 1, inf )  = domain of j(x)

You mean \(av \le \frac{v!}{v^{2}-v+1} \le \frac{v!}{v^{2}-v} = 1 \times 2 \times \dots\) right?

x + 5  <  8

If for some reason we cant solve this inequality the normal way, then we can do it like this

x + 5  =  8

x  =  3

And then we know that

the values that make the original inequality,  x + 5 < 8 , true will be either  x < 3  or  x > 3 .

I thought about it because when you are trying to find the values that make a quadratic function greater or less than zero, we have to do it like this and test points in an interval.

....Is that a good explanation??

I really hope you mean mol, the unit because otherwise, I'm never eating chocolate again. Could you please clarify?

The coordinates didn't show. Could you please fix this?

Well, then, let's just hope it makes it into the "Sticky Topics" section.

One question, hectictar...

You write that

" So the  x  values that make  -1 <  (x +1) / (x - 1)  < 1  true will either be  x < 0  or  x > 0 ."

How did you determine this  ???  

The domain of  f(x)  is  -1 < x < 1

So the domain of  f( \(\frac{x+1}{x-1}\) )  is  -1 < \(\frac{x+1}{x-1}\) < 1

*edit* (I was unhappy with my previous answer.)

thank you so much!! :)

2 / 125  =  

2  * (1/5)^3  =

2 * .2^3      and since a terminating decimal raised to a positive power will terminate, 2 / 125 will also terminate

You are taking 4 away from the 13

remember to take away means to subtract

Since You gave away 4 of your cookies you still have 9 left. 

Do You understand now?

3x+y=20    ⇒  y =  20 - 3x   (1)

2x+3y=18   (2)

Sub (1)  into (2)  for y

2x + 3 [ 20 - 3x]  =  18    simplify

2x + 60 - 9x  =  18

-7x + 60  = 18       subtract 60 drom both sides

-7x  =  -42            divide both sides by -7

x = 6

And using (1)    y =  20 - 3(6)  =  20 - 18  =  2

HELP!! URGENT!! 

There is a row of Pascal's triangle that has three successive positive entries,"a" "b"  and "c"
such that "b" is double "c"
and "a" is triple "c"
If this row begins "1,n,"  then find n.

Help me too? 

solve the systems of equations:

3x+y=20
2x+3y=18     (no graph)