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 #3
avatar+471 
+1
Oct 25, 2017
Oct 24, 2017
 #3
avatar+2446 
+2

Doing this problem requires one to consider a few cases. 

 

Firstly, I will solve for x in the first given equation.

 

|xy|=950 Drop the absolute value bars and split this equation into a positive and negative answer.
xy=950 xy=950

 

Add to both sides in both cases to isolate x.
x1=y+950 x2=y950

 

 
   

 

Now, let's solve for z in the second equation in the exact same fashion. 

 

|yz|=987 Drop the absolute value bars again.
yz=987 yz=987

 

Subtract y from both sides.
z=y+987 z=y987

 

Divide by -1 to fully isolate.
z1=y987 z2=y+987

 

 
   

 

In order to solve this problem, one must consider all 4 cases. I have created them all in a table for you! Then, simplify as much as possible.
 

Case 1: |x1z1| Case 2: |x1z2| Case 3: |x2z1| Case 4: |x2z2|
|y+950(y987)| |y+950(y+987)| |y950(y987)| |y950(y+987)|
|y+950y+987| |y+950y987| |y950y+987| |y950y987|
|950+987| |950987| |950+987| |950987|
|1937| |37| |37| |1937|
1937 37 37 1937
       

 

Therefore, |xz|=37or|xz|=1937

.
Oct 24, 2017

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