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Can anyone at least try from the information I gave you?

How did you discover this?.....

What is the equation again?

True, ProMagma......very true.....!!!!!

Correct - A - Mundo.....!!!!

√ [ -25]  =

√ [ -1 * 25] =

√-1  * √25  =

i * 5  =

5 i

How didn't I see that on the test...

(x² + 9)(x + 3)(x - 3), right?

5i; you are taking the square root of a negative number, so you can remove the negative and multiply it on the outside by i. There is no minus sign in front, so the answer will be 5i.

(x ^2 + 9)  ( x^2 - 9)

So far...so good...but notice that   x^2 - 9  is also a difference of two squares....

Can you finish it helperid ???

16x^2  +  9  = 0

16x^2   =   -9         divide both sides by 16

x^2  =  -9/16         take both roots

x  =±√(-9/16)  =   ±√ [ -1 * (9/16) ]

x =  ± (3/4) i     ⇒  first answer

\(f(f(3)) + f(f^{-1}(4)) + f^{-1}(f^{-1}(5))\)

f (3)  = 5

f(f(3))  = f (5)  = 8

And   f( f^-1) (4))   =  4

And   f-1 ( f^-1(5) )      =  f^-1 (3)  =  2

So

8+ 4  + 2  =  14

CORRECTED  !!!!

[x^2 + 3x - 28] / [ x^2 - 7x + 12 ]

[ (x + 7) (x - 4) ] / [ (x - 4) ( x - 3) ]  =

(x + 7)  / ( x - 3)

I think it is

3f^2+4+5/f^2

I hope!

-11x^2 = x + 11    rewrite as

11x^2 + x + 11  = 0

The discriminant is

1^2  - 4(11)(11)     which is < 0

So.....anytime the discriminant < 0.....we have no real solutions

Oh My Goodness This Is Hard Stuff!!

We want to solve this

[12 + x ]  /  [15 + x]  =  .85    where x is the consecutive number

Cross-Multiply

12 + x  =   .85 [ 15  + x ]  simplify

12 + x  =  12.75  + .85x     subtract  .85x, 12 from both sides

.15x  =  .75       divide both sides by  .15

x =  5    ⇒    5 consecutive FTs

Teacher: "Who knows 5+5=?" Little Johnny: "11" Teacher: "Take out your hand from trousers pocket and count with your fingers."

Melody recommended me to be a mod....I didn't have much to do with it....LOL!!!!