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so i was right

Note, NSS....the two roots are  are x = -1 and x  = 1

And when x  = 0.....y is negative

Notice that letting x = 0   in the first equation means that y  = -2...this means that the point (0, -2)  should be on the graph....but this point clearly isn't on the graph

And letting x = 0   in the second and fourth equations, means that y is positive.....and that's not possible on the graph when  x = 0

So....the third equation must be correct.....!!!

x²-1=0 aka third one

hah, never mind. i got it. 63+5=68. x=68. 44--19=63.x=-19. thanks anyway.

thanks sosososososoosososoososo much 

5 * 8^4x = 376

Divide both sides by 5

8^(4x)  =  376/5

Take the log of both sides

log 8^(4x)  =  log (376/5)   = log (72.5)    and we can write

(4x) log 8  =  log (72.5)     divide both sides by   4 log8

x =  log (72.5) / [ 4 log (8) ]

log ₄ 25  = x

When  we have log_a b  = x  ....we can solve this with the change of base theorem  which says that

x  = log b / log a

So....this evaluates to

log 25 / log 4  ≈  2.32

Yep Thanks!!!

f(x)  =  -0.25(6)^x + 2 - 1         The y-intercept is  f(0) .

                                                To find f(0), replace every  x  in  f(x)  with  0 .

f(0)  =  -0.25(6)^0 + 2 - 1

f(0)  =  -0.25(1) + 2 - 1

f(0)  =  -0.25 + 2 - 1

f(0)  =  0.75                              The y-intercept is  0.75 .

Now it makes sense, thanks dude

Exactly....!!!!

We have a decagon ....the sum of the interior angles in a decagon is  (10 - 2)*180  =

1440°

[ Hint : The 80°  exterior angle means a 360 - 80  = 280°  interior angle  ]

So we have that

[ 107 + 126 + 325 + 125 + 95 +  x + 90 +  280 + 47 + 130 ]  = 1440

Rearrange as

1440 - [ 107 + 126 + 325 + 125 + 95 +  90 +  280 + 47 + 130 ]  = x

1440 - [ 1325 ]  =  x

115°  =  x

Thanks for the answer but when u said 'the midpoint theorem' is it like x₁+x₂/2 and y₁+y₂/2 ??

The functions are inverses of each other

The graphs of functions are symmetric to each other over the line y = x

1n (121) =4.7958

We need to use the midpoint theorem here

[ 1 + p ] / 2  =  8

Multiply both sides by 2

1 + p  = 16     subtract  1 from both sides

p  = 15

And to find q, we have that

[ 7 + q ] / 2  = 2

Multiply both sides by 2

7 + q   =  4      subtract 7 from both sides

q  = -3

Thanks.  I am also trying to get a solution that corresponds with one of the answers.

None of these

We know that    m - 2  = n  ⇒    m = n + 2

So....using the Pythagorean Theorem....we have that the remaining side =

√ [ m^2 - n^2 ]

√ [ ( n + 2)^2  - n^2 ]      simplify

√ ( n^2 + 4n + 4  - n^2 )

√  [4n + 4]

So....the square of this side  =    4n + 4     [ in terms of n ]

Is the base 10 or something else?

thanks

All we need to do  to find the scale factor is to take the ratio of the x coordinate of A' to he x coordinate of A

So we have

-0.6 / - 3  =  .6 / 3  =    (6 /10)  / (3 /1)  =  (6 / 10) * (1/3)  =  6 / 30  = 1/5

Since angle(X) is congruent to angle(A),

          angle(P) is congruent to angle(W),

          angle(G) is congruent to angle(D),

and   angle(Y is congruent to angle(Q),

and the ratio of the corresponding sides have the same scale factor, 0.875,

quad(XPGY) is similar to quad(AWDQ)

To find the image, take the x- and y-values of each corner point of the original figure and multiply it by the scale factor.

Therefore, corner point (-3,-2) becomes corner point (-6,-4), 

                  corner point (-1,1) becomes corner point (-2,2),

                  etc.