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why wont my pictures upload!!!

I'm not great at Physics....but....I might be able to answer a few of these

Acceleration  =   Change  in Velocity /  Change in Time =   [ 30 - 0 ] / [ 0 - 4.2 ] =

[ 30m/s]  / [ - 4.2 s]  ≈   - 7.14 m/s^2

Omg i have never been able to see a staff members birthday! Happy Birthday Cphill!

ps i deleted the pic. Later people.

Here are the constraints

x  + y  ≤ 36

y  ≥  3x

And we seek to maximize this

2x  +  3y

Look  at the graph of the constraints :  https://www.desmos.com/calculator/ezk3fnwmsj

The max occurs at the only corner point,  (9,27)

So......the max profit  is

2(9)  + 3(27)  =

18  +  81   =

$99

Thanks, Asad....!!!

1. (a^2-6)^2 - (4a + 6)^2

This is a difference of squares

[ (a^2 - 6) + (4a + 6)]  [ [(a^2 - 6) - (4a + 6) ]  =

[ a^2 + 4a]  [ a^2 - 4a - 12 ]  =

[a] [a + 4 ] [a - 6] [a + 2]

2. (2m -3)^2 - (8m^2 - 4)^2

Same thing

[ (2m - 3) + (8m^2 - 4) ]  [(2m - 3) - (8m^2 - 4) ]  =

[ 8m^2 + 2m - 7 ]  [ -8m^2 + 2m + 1 ]  =

[8m^2 + 2m - 7 ] [-1] [8m^2 - 2m - 1]  =

[8m^2 + 2m - 7 ] [-1] [ 2m - 1] [ 4m + 1 ] =

- [8m^2 + 2m - 7 ]   [ 2m - 1 ] [4m + 1]  

3. (17p^2 -26) - (8p^2 -4)^2

(17p^2 - 26) -  [ (8p^2 - 4) (8p^2 - 4) ] =

( 17p^2  - 26)  -  [ 64p^4 - 64p^2 + 16 ]  =

 [ - 64p^4 + 64p^2 + 17p^2  - 42 ]  =

 -64p^4  +  81p^2  - 42    ⇒    this is irreducible

Let one of the parallel sides   = x......so the other is 22-x

And  the length of the  midline  = sum of the parallel sides / 2  =  22/2  = 11

Let the area of the smaller part  =  (h/2)(11 + 22 -x)  = (h/2)(33 - x)

Let the area of the larger part  = (h/2)(11 + x) 

And  (7/4)*area  of the smaller part   = the larger part....so.....

(7/4)*(h/2)*(33-x)  = (h/2)*(11+ x)

(7/4) (33 - x )   =  (11 + x)

7(33 - x)  = 4(11 + x)

231  - 7x   =  44 + 4x       add 7x to both sides, subtract 44 from both sides

187  =  11x         divide both sides by 11

17  = x

So.....one parallel base  = 17  and the other is  22-17  = 5

And their product  = 17 * 5   =  85

17  ≥  7    so    f(17)   =   17 - 13   =   4

4  <  7    so    f(4)   =   4² - 4   =   12

12  ≥  7    so    f(12)   =   12 - 13   =   -1

f(  f( f(17) )  )   =   f(  f( 4 )  )   =   f(  12  )   =   -1

The angle would be 101 degrees.

Sin θ = 14/16

θ = sin^-1 (14/16)

θ = 101 degrees

:D

Oh it would be positive 2 so 79 :D

The only (pepper, cheese) = (x,y)  choice that is in the shaded area is the first choice (43,25)

The only (carrot, cucumber )   =   (x,y)  of the choices that is in the shaded area is 30 carrots 21 cucumbers

Using the one with two closed dots, put one closed dot goes on  -7  and the other on  -2  .

0, 0, 0, 0, 0, 0, 1, 1, 1, 2, 2, 2, 3, 3, 3, 3, 3, 3, 4, 5

There are 19 numbers in total, and the middle two numbers are both 2, therefore the median is 2.

Is there another way to do this? Apparently 75 isn't correct :/

avg. number of pets per family  =  (total number of pets) / (total number of families)

total number of pets   =   0 * 6  +  1 * 3  +  2 * 3  +  3 * 6  +  4 * 1  +  5 * 1   =   36

total number of families   =   6 + 3 + 3 + 6 + 1 + 1   =   20

avg. number of pets per family   =   36 / 20   =   9/5   =   1.8

f (∛( -8) ) +  f (- pi) + f (√50 )  + f(9/2)

Edit

Sorry... I didn't see the absolute bars  in the first function....so ....the answer is

 l-2 l  +  (-3)^2   +  (8)^2  +  l 4  l  =

2  + 9   +  64   +  4   =

79

a₃₁  =   104    ......represents  the number of boys in Town A  who play soccer 

Girls  enrolled in basketball in Town B  =  b₁₂  =  94

B   -   A    =

6       14

8       -7

6        2

c₂₂  means that there are 7 fewer girls enrolled in lacrosse in Town B than in Town A

1.125 A  =

108        90

 72         99

117       135

4x - y + z = -5    ⇒   8x - 2y + 2z  =  -10    (1)

2x + 2y + 3z =10       (2)

5x - 2y  + 6z = 1        (3)

Add (1)  and (2)

10x + 5z  = 0        ⇒    2x  + z  =  0   ⇒   z  =  - 2x     (4)

Add (2)  and (3)

7x + 9z  = 11    (5)

Sub (4)  into (5)

7x + 9 (-2x)  =  11

7x - 18x = 11

-11x  =  11

  x  =  -1

So.......z   =  -2(-1)  =  2

And using  4x - y + z = -5   to find y, we have

4(-1) - y +  2  =  -5

-4   -  y   +  2   = - 5

-2 - y   =  - 5

-y  =  - 3

y  =  3

So    {x, y, z }  =   ( -1, 3,  2 }

√ [ 5x + 4 ] - √x  =  4          rearrange as

√[5x + 4 ]  =  4 + √x          square both sides

5x + 4  =  16  + 8√x  +  x

4x - 12  =  8√x           divide both sides by 4

x -  3  =  2√x             square both sides again

x^2  - 6x  +  9   =   4x

x^2  -  10x  +  9   =   0           factor

(x - 9) ( x - 1)   = 0

Setting both factors to 0  and solving for x leads to two possible solutions :

x  = 1     and  x   = 9

Checking these in the original equation.....only x  = 9   will be a true solution

Second one

a. (7,6)  and (1,12)  best model the data

b.   Slope  =  [ 12 - 6 ]  / [ 1 - 7 ]  =  6 / -6  =  -1

c.  Point-slope form     y - 6  =  -1  (x - 7 )

d. Slope-intercept form      y  =  -1x  +  13

e.  Least squares  equation  :  

y = -1.0357142857143x + 13.142857142857

Notice that this is very close to the slope-intercept form !!!! 

First one

a.

Order the data from low to high

61, 71, 73, 76, 78, 85

Minimum  =  61

Median  = Q2 =  [73 + 76 ] / 2  =  149/2  =  74.5

Q1   = [61 + 71 ] / 2  =  132/2  =  66

Q3 = [ 78 + 85 ] / 2  =  76.5

Max  =  85

b.   Mean   =  [ 61+ 71+ 73+ 76 + 78+ 85] / 6   =  444/6  =  74

c.      61  -  74          - 13                169

         71 -  74           - 3                      9

         73 -  74           - 1                      1

         76 -  74             2                       4

         78  - 74             4                     16

         85  - 74            11                   121      

                                           Sum      320

d. Standard  deviation  =   √ [320 / 5 ]  =  √64   =  8

look it depends on what the question is asking

one 5'8" adult male body

Thanks, Julius....!!!