Well, If the numbers all go first it will be 6^3*26^4
Now if they are all mixed up you are testing me. Probability is a bit of a joke on this forum.
Now let me see. there are 7 items in the code.
I'm going for 7C3*6^3*26^4 =
$${\left({\frac{{\mathtt{7}}{!}}{{\mathtt{3}}{!}{\mathtt{\,\times\,}}({\mathtt{7}}{\mathtt{\,-\,}}{\mathtt{3}}){!}}}\right)}{\mathtt{\,\times\,}}{{\mathtt{6}}}^{{\mathtt{3}}}{\mathtt{\,\times\,}}{{\mathtt{26}}}^{{\mathtt{4}}} = {\mathtt{3\,454\,738\,560}}$$
It is probably wrong. I've got other things to do. See you later! 