Slowing moving towards those 1000 posts

$${\mathtt{169}}{\mathtt{\,\small\textbf+\,}}{\mathtt{1}} = {\mathtt{170}}$$

$$\frac{2\sqrt{45}+\sqrt{90}+5\sqrt5}{\sqrt{15}}\\\\
=\frac{2\sqrt{9*5}+\sqrt{9*5*2}+5\sqrt5}{\sqrt{3*5}}\\\\
=\frac{2\sqrt{9}\sqrt5+\sqrt{9}\sqrt5 \sqrt2 +5\sqrt5}{\sqrt{3}\sqrt5}\\\\
=\frac{6\sqrt5+3\sqrt5 \sqrt2 +5\sqrt5}{\sqrt{3}\sqrt5)}\\\\
=\frac{\sqrt5(6+3 \sqrt2 +5)}{\sqrt3\sqrt5}\\\\
=\frac{(11+3 \sqrt2)}{\sqrt3}\\\\
=\frac{(11+3 \sqrt2)\sqrt3}{\sqrt3 \sqrt3}\\\\
=\frac{11\sqrt3 +3 \sqrt6}{3}\\\\$$

Aye! But the power of Majesty maketh that which be less than, now be greater than.

M^-1

I see, I see, but in truth she be not more than 3 times charmed. 

Still charmed she is - undeniably the truth this be!

For sure, the Kitty be no less than 3 times charmed, my Lady.

M^-1

Thank you Sir.  I see thee be generous with thou phalanges too.     (thumbs up)

In kind I shall reward thee.  The cat shall curl upon my lap and together we be warmed and charmed.

I guess you are referring to the aim to replace pi by tau (=2pi).  It'll never fly!

If Her Majesty see a black cat, it bringeth thee good fortune, and to the cat a destiny of charm.

M^-1

Like WOW!

(Message given) info: enter a more detailed answer..

Like WOW again.

I had to stop laughing long enough to write this!

Err I mean....

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The Queen is most impressed Chiurgeon Tud.

The Quadratic is indeed enchanted. 

It doth indeed appear that thou art not only a fine surgeon but a gifted conjerer as well.

I trust this is not Black magick that you show us here. I did see a black cat on this morn.  

A worry it is - indeed, Sir,  it is a worry!

Lady Guinevere, Queen of all Camelot.

I am not saying that the statement is true  I am saying that it is a statement and the statement is false.

Like

Statement: All dogs have 5 legs and all cats are mammals.

This logic statement is FALSE

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In your example the  statement is 1*0*1=1 And this statement is FALSE.  I don't particlualy like the zero and one analogy but I can see that it also works.

PEDMAS or BODMAS

Parenthesis (Brackets) first

Exponents (Power Of) next

Division and Multiply are equally important - Do them from left to right

Addition and Subtraction are equally important - Do them from left to right.

Okay zegroes, I'll give you back your points when you fix your answer.  

Chris might call them equally correct but I don't and I don't want the asker to think that your (original) answer is correct because it is not!

the circumference of 2cm is a circle with a radius of .32 cm

Yes, You indeed can.

On the top, there is a toolbar.

Yea, Your Majesty, If this be true, then shall I boweth to Takahiro Maeda-sana, with great respect!

M^-1

Perhaps TakahiroMaedo be such a god. For this fine person doth claim to know of such a divine soution!

Greetings Your Majesty,

It seemeth that only a god knoweth the solution by one operator. I know not the deity which hath such knowledge.

Sir Cphill findeth a solution with two. Perhaps it be all the practice with the zeros of the gods.

In your service.

Morgan Tud M^-1

Sir See Phil doth admit to cheating by using 2 fold operators.  

Thou uses Cos, ! and +  . Doth this mean thou expand upon the truth one and one half times more than Sir SeePhill?

Tis impressed I am on both accounts. Tis wonderous what answers thee both hath salvaged.

Jboy is right we do need to know the compounding period.

But also you have said 5%.   I assume that this is per year but you have not specified this. 

so you need 5%p.a. is this is what you mean.   

Aye, Sir CPhill, the skill ye have with zeros be amazing!

Here be other solutions: Though this be three operators. 

$$(cos(0) + cos(0) + cos(0) + cos(0) + cos(0))! =120 \\$$

Extending the logic of Sir Alan this be true:

$$(not(0)+not(0)+not(0)+not(0)+not(0))! =120$$

M^-1

the reason that your question did not get answered earlier is that you did not specify what 2cm was.

Is it the distance from the centre to the circumference which is called the radius.

Or is it the distance all the way across which is called the diameter.

In his answer Zegroes has assumed it its the diameter.

C = pi * diameter.

C=pi*2

$${\mathtt{2}}{\mathtt{\,\times\,}}{\mathtt{\pi}} = {\mathtt{6.283\: \!185\: \!307\: \!179\: \!586\: \!5}}$$

C=6.28cm correct to 2 decimal places.

Right? Parenthises equations multiply divide addition then subtraction...P.E.M.D.A.S right my bad..... 

Dont you use pi in this situation 3.14*2=6.28?

Rosalas post ill have lots of questions when i come back from school....Uh oh THE KOOL AID disease!!!!!Duh duh DUH

Actually...in some sense, " ! " represents an "operator"........so I actually "cheated" because I used the "+" operator, too......

But I'm willing to forget about it if you are........