All Answers 356732 Answers

1. Correct!  

2. Yes ! 

3.  Common angle, but ratios of sides are not the same....sooooooo....

4. Common angle and sides ratios are the same .....soooooo.....

32 y/m  * 1 m/60s * 36 in/yd = 19.2 in/s

.85km/s   will never equal quarts/min

80 m/h x 5280 ft/m x 1h/3600s = 117.33 f/s

20 oz/min x 1qt/32oz x 60min/hr x 24hr/day = 900qt/day

See how it is done??? 

Welcome to the team. have any qestions?

Welcome Arriane

You have any questions

Welcome to our Mathematical Menagerie, Arriane !   Have any Q's? 

Here is one way to go about getting the answer:

= 15 *3 *sqr(32)*sqrt(8)

=45  sqrt (2^5 * 2^3)

=45 sqrt (2^8)

=45(2^4)

=45(16)

=720

Here is another

15*3* sqrt(32*8)

45 sqrt(256)

45*16=720

Thanx, Alan....good to remember...and simpler!

There are 2 pi radians in a complete circle

pi x 2r = circumference

pi x 2 x 26.9 =169 cm

fraction of this circumference intercepted by this central angle

?/169 = 9pi/5  /  2pi

?= 152.1 m

By definition the angle in radians is simply the arc length divided by the radius.  

Circumference = pi * d   = pi * 2r = 12pi   cm

there are 2pi radians in a complete circle of which this Q is seekong a fraction

   5.4 / 12 pi =  ?/(2 pi)       ? = .9 radians

You can do this on the webcalc calculator as follows:

Enter:

sum(100*1.1^n,n,0,11)

Thanks To all of you!!!

A committee of three people is to be randomly selected from a group of three men and two women, and the chairperson will be randomly selected from the committee. What is the probability that the committee will have exactly two women and one man, and that the chairperson will be a woman?

Express your answer as a common fraction. 

\(\begin{array}{|rcll|} \hline && \left[\dfrac{ \binom22\binom31 } {\binom53} \right]\times \left[ \dfrac{ \binom21\binom10 } {\binom31} \right] \\ &=& \left[ \dfrac{ 1\cdot 3 } {\binom52} \right]\times \left[ \dfrac{ 2\cdot 1 } {3} \right] \quad & | \quad {\binom53} = {\binom52} = \dfrac {5}{2}\cdot \dfrac{4}{1} = 10 \\ &=& \left[ \dfrac{ 3 } {10} \right]\times \left[ \dfrac{ 2 } {3} \right] \\ &=& \dfrac{ 2 } {10} \\ &=& \dfrac{ 1 } {5} \\ \hline \end{array} \)

Here’s another way of looking at it:

Suppose a, b and c are men and x and y are women. The total possible arrangements are:

abc

abx 

aby 

acx 

acy 

axy 

bcx 

bcy 

bxy 

cxy

Of these ten, three have two women and one man, so Probability of this style committee is 3/10.

Probability of such a committee having a woman as chair is 2/3.

Hence overall Probability is (3/10)*(2/3) = 1/5 as EP obtained.

Take your spam and shove it up your FUCKING A S S!!!

(1/a) - (1/b) = (1/c) 

make a the subject

\(\begin{array}{|rcll|} \hline \dfrac{1}{a}-\dfrac{1}{b} &=& \dfrac{1}{c} \quad & | \quad +\dfrac{1}{b} \\\\ \dfrac{1}{a} &=& \dfrac{1}{c} +\dfrac{1}{b} \\\\ \dfrac{1}{a} &=& \dfrac{1}{c}\cdot \dfrac{b}{b} +\dfrac{1}{b}\cdot \dfrac{c}{c} \\\\ \dfrac{1}{a} &=& \dfrac{b}{bc} +\dfrac{c}{bc} \\\\ \dfrac{1}{a} &=& \dfrac{b+c}{bc} \\\\ \dfrac{a}{1} &=& \dfrac{bc}{b+c} \\\\ \mathbf{a} & \mathbf{=} & \mathbf{\dfrac{bc}{b+c}} \\\\ \hline \end{array}\)

I seem to almost never get these correct.....still trying to get this probability stuff to 'click' in my mind. Here is my best guess:

Ways to fill the committee   5 c 3 = 10  possible ways to pick from the pool of 5 people

    of these 10 selections there are 3 possibilities that have 2 women and one man

          so....so far  3/10 chance for 2 women and one man on the committee

With any of these choices, there is a 2/3 chance of picking a woman for the chair position

so  3/10 x 2/3 =  6/30  =1/5  chance  for    2 women 1 man   and woman chair .

Thank you, CPhill

Thanx, I understand that.....BUT, I was merely pointing out that the question is worded improperly.

    you start out with 100 and then for 12 MORE months you add 10% (per the question)

'you set aside 100 dollars

'for each month thereafter, you plan to set aside 10% more than the last month for 12 months

So it is a series of 13 payments essentially....first one 100  then twelve more.

It is like saying , in February , I put 100 in the bank....then starting in July I made a deposit of   110

(1st increasing deposit) ...then I did this ELEVEN MORE times for a total of TWELVE more  deposits after the 100.....  Do you see what I am trying to say?    ' for each month thereafter   ....for twelve months'

 I see in the poster's answer he only made increasing deposits ELEVEN more times....so what the question should say is you start with 100 then for ELEVEN months you add 10% to the previous month's deposit.   

   Anyway....minor point.   Just how I read the question.....but apparently no one else did, so I'll go with the flow......      

Thanx  .... G'Day !

Common denominator for the first two terms is

  (x-3)(x+8) = x^2+5x-24

so (cross multiplying the first two terms) results in

{c(x+8)  + d(x-3) }/(x^2+5x-24)  =  (4x-23) / (x^2+5x-24)    

   Both left and right sides have the same denominator ....so the numerator is equal

c(x+8) + d(x-3) = 4x- 23

cx + 8c + dx - d3  = 4x- 23

so cx + dx = 4x   (1)  and  8c-d3 = -23   (2)

    c+d = 4

         d = 4-c     substitute this into (2)

8c -3(4-c) = -23

8c-12+3c = -23

11c= -11

c = -1               d=4-c = 4-(-1) = 5       The product of  c x d  = (-1) x 5 = -5        

Thanks!

Are the ratios of the side lengths similar?

16-----> 40   is a scale factor of  40/16 = 2.5

is the other side scaled by the SAME factor?

12------>30      scale factor is  30/12 = 2.5

Yes , they are similar.

Area x height = volume

area of right triangle = 1/2 leg1 x leg2

R one  volume =  1/2 x 30 x 40    x  height  = 600h

L one volume   =  1/2 x 12 x 16    x  height  =  96h

     the one on the R will have greater volume   600h/96h = 6.25 times greater volume