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I guess you should use the following formula:

V=4/3 π R³   V=4/3 * 3.14 * 4,5³ 

V=381,7

If we rearrange: 

xy=8 

y = 8/x 

Since there is an x in the denominator this makes it a reciprocal graph. 

That's disgraceful CPhill.

Why are you doing this persons homework for him/her ?

Help by all means, but you shouldn't be answering the whole of the question.

IF

$y=(4t-3)-8\\ y=4t-11\\ \frac{dy}{dt}=4\\~\\ BUT \;\;IF\\ y=(4t-3)^{-8}\\ \frac{dy}{dt}=-8(4t-3)^{-9}*4\\ \frac{dy}{dt}=-32(4t-3)^{-9}\\$

nice

I would not have thought to do it like that EP but I cannot fault your logic...

sounds good to me  

The angle PAD is equal to the angle ABD, so the triangles PAD and PAB are similar (since the angle APB is common to both triangles).

That allows you to write down the ratios

$\displaystyle \frac{AP}{PB} = \frac{PD}{AP}=\frac{DA}{AB}.$

If you now do the same thing for the triangles the other side of the line PB, and compare the two sets of ratios, you should see that the result drops out in one line.

Tiggsy

Could you  define the term ' point estimate ', ( for the non statisticians amongst us ) ?

Good work H !

you know that when you factor an expression as you did you can see for yourself if it's correct by the reverse operation ie multiply the factors out and then simplify to get the original expression.....instant positive feedback...

cheers

That is an amazing way to annoy the H E L L out of everyone.

Let’s have a vote: My helpful posts of a s s-biting content or bible verse.

If the votes aren’t decisive, I’ll post both.

just use lots of parentheses ( )

volume of cone   =   ( 1/3 )( π * radius² * height )

diameter  =  12 cm

radius  =  diameter / 2

radius  =   12 cm / 2

radius  =   6 cm

height  =  16 cm

Use these values for the radius and height to find the volume.

volume of cone   =   ( 1/3 )( π * (6cm)² * 16cm )

volume of cone   =   ( 1/3 )( π * 36cm² * 16cm )

volume of cone   =   ( 1/3 )( π * 36 * 16 )   cm³

volume of cone   =   ( 1/3 )( 576π )   cm³

volume of cone   =   192π   cm³

volume of cone   ≈   192(3.14)   cm³

volume of cone   ≈   602.88  cm³

i assume the line plot is the % difference, the orginal 95% vs 92% has a difference of 3%,

the 10 random values center around 3% and 3% has the most occurances of the 10.

the average value for the 10 is 2.9%, so that is within .1 of the orginal 3%

so it should be significant, not sure what criteria you are supposed to use?

is there a p or z test involved?

     -4y² + 3xy - 12y + 9x

=

     y(-4y + 3x) + 3(-4y + 3x)

=

     (-4y + 3x)(y + 3)

=

     (3x - 4y)(y + 3)

$\quad\frac{\frac{x^2+x-12}{x-2}}{\frac{3x^2+11x-4}{x^2-4}}\\ =\\ \quad\frac{x^2+x-12}{x-2}\cdot\frac{x^2-4}{3x^2+11x-4} \\ =\\ \quad\frac{(x+4)(x-3)}{(x-2)}\cdot\frac{(x+2)(x-2)}{3x^2+12x-x-4} \\ =\\ \quad\frac{(x+4)(x-3)}{(x-2)}\cdot\frac{(x+2)(x-2)}{3x(x+4)-1(x+4)} \\ =\\ \quad\frac{(x+4)(x-3)}{(x-2)}\cdot\frac{(x+2)(x-2)}{(x+4)(3x-1)} \\ =\\ \quad\frac{(x+4)(x-3)(x+2)(x-2)}{(x-2)(x+4)(3x-1)} \\ =\\ \quad\frac{(x-3)(x+2)}{(3x-1)} \qquad\text{and}\qquad x\neq-4\, \qquad x\neq2\\ =\\ \quad\frac{x^2-x-6}{3x-1}$

It's correct!!

It says waiting for moderation. 

Couple of ways to go about this...let's do it the easy way

1/3 lnx + .69315 - 1.0986 =3      Simplify5

1/3 ln x = 3.4055

ln x = 10.164

x =  27346.67

ANOTHER way

ln (((x^1/3) (2)) /3) = 3

(x^1/3  *2)/3 = e^3

x^1/3 =  3/2  *  e^3

x  =  (3/2 * e^3 )^3 = 27347. 9    (difference due to rounding in the first example)

I don't know.. but I am checking my answers so Ill know that I am working my problems correctly.