I believe we don't need to use a table of values.
The question is saying, when you plug a number, \(x\), into the two functions, the two results are the same.
Let's call the number, \(n\).
When we plug \(n\) into \(f(x)\), we get \(n^2 - 6n + 8.\)
When we plug \(n\) into \(g(x)\), we get \(n - 2\)
The problem states that these two values are equal, so we can write the equation:
\(n^2-6n+8=n-2\\ n^2-7n+10=0\\ (n-5)(n-2)=0\\ n_1=5\ n_2=2\)
I hope this helped,
Gavin