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does this seem like a good explantion 

First thing to do is to find the equation  in y=mx+b form ..... so our equation is y=3/1x-3    we found our slop with rise over run we found our "-3" from the y-intercept.  now all we have to do is to plug the points (4,-3) into out equation if we get a true statement then its is a solution if not it will be false ...-3=3/1(4)-3 .... solving it i get false 

good boi

yeah, correct one is selected

I agree with..Holdmybeer? The answer is "No". The shaded area or the line does not go anywhere near the point.

Find the co ordinates of the orthocentre of a triangle whose

vertices are (1,3) (-7,-6) and (8,-1).

I think no, but I may be wrong

M = log (I/s)

10^m = I/s

10^m2 / 10^m1  =  I2/s  /  I1/s = I2/I1

I1  *  10^m2/ 10^m1  = I2          Let I1 and m1 refer to the magnitude 6

I1 * 10^8/10^6 = I2

I1 * 10^2 = I2

i1 * 100 = I2              this shows that I2  (magnitude 8) is 100 times the intensity I1 (magnitude 6)

Total cost for option 1   is $ 53 times the number of tickets you purchase + $10  for shipping

    let y = total cost

then    y = total cost = 53 * # tickets you buy plus 10

      Let x= #tickets

 then y = total cost= 53 x + 10

    y= 53x + 10        I have no other way to make it any clearer.....I hope you 'get it' now

I know the answers but i don't know how to get it

Good luck.....I hope it is getting clearer! 

Option 1   y = 53 x + 10

Option 2   y = 55 x

Thank you so much! I apologize for asking but I've been having a difficult time. I appreciate your help. Have a fantastic day/night!!

Each two mole of K  used results in two mole of KCl....

K  mole wt 39.0983 gm/mole

      2.5 gm  is   2.5 gm/ 39.0983 gm/mole = .063955 mole of K

This will produce the same number of moles of KCl

KCl mole weight = 39.0983 + 35.45  gm = 74.5483 gm

.063955 mole  x   74.5483 gm/mole  = 4.768 gm of KCl

im great

How are you? I am fantastic

We can easily eliminate (B) and (D), for not having -9 for one of the coefficients. Since it has to be -2 instead of 2, the only answer is (C), the third option. 

Okay, again, let's try to solve here for the solution of the system.

Here, we can use elimination, or if you want to try; substituion. 

We have x-y=3 and 7x-y=-3. If we add subtract both equations, the y's will cancel out, so that's good!

Therefore, we get x-7x=3-(-3), which is -6x=6 and x=-1. 

Plugging the value of x for the value of y, we attain -1-y=3, -y=4, y=-4. So, it is a solution to the system! (B) works.

 We can try plugging in this system to see if this works for both equations. Doing so, we get -1-(-4)=3, -1+4=3, True!, (C)

And, for the second equation, 7(-1)-(-4)=-3, -7+3=-3, Yes! So, (E) works!

Thus, the answer is (B), (C), and, (E).

good luck man

maybe

yeah we both have a way to go