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yeah but its good knowing you are making something to help someone else

K-9 Is in the building.

i help out in construction of new houses and when i'm at home i'm a game tester 

That must be scary! I hope everything turns out okay.

eh its good it wasn't my first all-nighter 

I am exhausted because I had to work all night

Oh ok np then!

See if this solution will satisfy you!  https://web2.0calc.com/questions/help_92263

good thanks

I'm fine,you?(Post it like off-topic)

My "Word Processor" counts 102 characters WITHOUT spaces! So, 18/102 =3 / 17

A slight adjustment in the formula given above, since whether at the beginning or at the end of a period, it makes NO difference in the final outcome for one lump sum payment. The "beginning" or the "end" of a period makes a difference ONLY with regard to "Periodic Payments". So, the above formula should be the stated as follows:

n = $1 x [1 + r]^t. Now, you can solve for "t"

t =log(n/$1) / log(1+r)

Note: You may try this for yourself by using this online financial calculator:

https://arachnoid.com/finance/

I have no idea what you are on about Bambam89. 

I have struggled unsucessfully with this question before.

Tiggsy's outline is excellent.     THANKS TIGGSY     

I will fill the blanks in for you a little more Bambam.

Here is the initial pic that Tiggsy has described.

I do not have a lot of time now but Tiggsy told you to :

1) use the sine rule to get x in terms of theta and b

2) use the sune rule to get y in terms of theta and b

3) recognixe that  a = x+y  and hence express a in terms of theta and b

this is the outcome you should be able to get.

\(a=x+y=b(1+\frac{1}{\sqrt3})(cos\theta+sin\theta)\)

See if you can get to this point and then see if you can follow Tiggsy's instructions to finish the problem.

You can let me know how you get on if you want and maybe I can help you more if you need it.

You may need to send a note with the address to me by private message to get my attention though, otherwise i may not see your post.

Thanks, that was definetly it.  I really appreciate the help!

A slightly simpler way of looking at this is to note that the expected number of games won by B is (4/5)*30 = 24.

Number of games apparently won by B: 

A:   23

B:   24

C:  15

D:  25

Clearly C is suspicious!

n =1 * ( 1 + r )^t *(1 + r), solve for t, where n=FV, $1 =PV, r=Rate per annum, t=Number of years.

t =log(n / (r + 1)) / log(r + 1)