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the number at the top of the summation... the last index of the sum

I have nothing but confidence in your ability to do simple arithmetic.

O no man

Hope you r safe!

\(m=2\).

For me I just did guess and check, starting with one and making my way up.

You are very welcome!

:P

The mean is simply the average.

City 1 = \(10+20+23+16+12+6=87\) , so to find the mean we do \(87/6\) and get 14.5.

City 2 = \(6+16+22+18+8+1=55\) , so to find the mean we do \(55/6 \) and get 9.17 when rounded to the nearest hundreth.

The mean of City 1 was 14. inches and the mean of City 2 was 9.17 inches.

You are very welcome!

:P

Yes, I believe you are completely correct!

You are very welcome!

:P

See bottom line:

Ok, thank you.

Ok thank you!

Multiply your first equation by -3 to get

-45x-36y = -877.50     the add it to the second equation to get

-26y=-130       solve for y =$ 5

Sub y= 5 in to either equation

15x +12(5) = 292.5

15x=  232.5

x= $15.5

Solve the following system:
{15 x + 12 y = 292.5 | (equation 1)
45 x + 10 y = 747.5 | (equation 2)

Swap equation 1 with equation 2:
{45 x + 10 y = 747.5 | (equation 1)
15 x + 12 y = 292.5 | (equation 2)

Subtract 1/3 × (equation 1) from equation 2:
{45 x + 10 y = 747.5 | (equation 1)
0 x+(26 y)/3 = 43.3333 | (equation 2)

Multiply equation 2 by 3/26:
{45 x + 10 y = 747.5 | (equation 1)
0 x+y = 5. | (equation 2)

Subtract 10 × (equation 2) from equation 1:
{45 x+0 y = 697.5 | (equation 1)
0 x+y = 5. | (equation 2)

Divide equation 1 by 45:
{x+0 y = 15.5 | (equation 1)
0 x+y = 5. | (equation 2)

x = 15.5
y = 5.

@ 'regular price' of $40/person she can take (including herself in the count)

       $300/$40/person = 7.5 ~ ~~ 7 people with $20 leftover

@ 'specil rate'  she can take   ($300-150)/ $25/person = 6 people

Why are you even taking the classes you are taking?

I don't want to be rude but it's pretty clear you aren't learning even the slightest bit from them.

This question is utterly basic.

Do you have any understanding of what correlation is at all?  Do you care?

Does the info in this class just not matter to your career pursuits at all?  I could understand that if it's an elective they forced on you.

But if you are going to need to have an basic understanding of this stuff to do whatever job you are hoping for just having us spoon feed you the answers is going to do you more harm than good in the long run.

so for b i got $240 for the regular price and for the group special $300...

Is this right? 

\(E[V_B] = 5000 \cdot 0.02 - 25 = 100-25 = $75\)

\(c_{reg}(n) = 40n \\ c_{special}(n) = 150 + 25n\)

a)   \(c_{reg}(n) = c_{special}(n)\\ 40n=150+25n\\ 15n=150\\ n=10\)

b) you can do this

c) use the special for 10 people or greater.  See part (a)

I don't see a limit in his question, am I missing something?

Lockdown has been lifted. Drugs were found inside the building and there was an unsafe person near the school.

the sum and product symbols are not defined to use fractional limits.  The index is only ever an integer.

what you can do is multiply the limit by whatever integer is in the denominator of the limit, in this case 2

and then divide the index by that scale factor in the body of the product term

You're answers look good to me.

the second question: Boxes 1 and 2 are true