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sorry im confused

Second one

Note that the height of the cylinder  =  2 * radius of the sphere

And the radius of the sphere  =   radius of cylinder

We need to find the radius of the  cylinder

432 pi  =  pi *  radius^2  * height

432 pi  = pi  * ( radius^2) *( 2* radius)      [ divide out 2, pi ]

216  =  radius^3      take the cube root of both sides

6  = radius

So....the volume of the sphere is

(4/3) pi * (radius)^3  =

pi *  (4/3) * 6*3

pi * (4/3) * 216  =

288pi  in^3

Thank you :D

4x^2 cube root 4x

\(\sqrt[3]{64\times4\times x^2 \times x^2 \times x }\) = \(\sqrt[3]{64}\sqrt[3]{\ x^6}\sqrt[3]{ 4\times x }\) = \(4x^2\sqrt[3]{4x}\)

Hope this helps!

I'm not sure I understand your question, but I'll give it a shot. 

With the equation y = 4.81x + 17.4, when $x = 15, y = 72.15 + 17.4, which equals 89.55. This rounds to [90].

When x = 9, y = 43.29 + 17.4, which equals 60.68. This rounds to [61].

You are welcome. 

First one :

Volume of a cylinder  =  pi * radius^2 * height

Radius of top cylinder  = 24/2  = 12

Height of top cylinder = 60 - 40  = 20

Radius of bottom cylinder  = 30/2  =  15

Height of bottom cylinder =  40

So....total volume  is

pi  [ 12^2 * 20  + 15^2 * 40 ]  =

pi [ 144 * 20  + 225 * 40 ]  =

pi  [ 2880  + 9000 ]  =

pi [ 11880 ]  = 

11880 pi  in^3

number 1 = x, number 2 = 155-x.

We have the equation $x = 4(155-x)$, which simplifies into $x = 620 - 4x$. Isolating x, we have $5x=620$, which simplifies into $x = 124$. The second number is $155-124$, which is $31$. Done, you are welcome. 

We have 2 numbers \(x,y\)

\(x=4y \) (1)

\(x+y=155 \)<=> We are replacing the (1) => \(4y+y=155\) <=> \(5y=155\) <=> \(y=31\)

so we are replacing in the (1) \(x=4\times31\)<=> \(x=124\)

so the two numbers? is \(31\) and \(124\)

Hope this helps!

See  this : https://www.desmos.com/calculator/lism3yazvg

Let the vertices of the quadrilateral be as follows :

A  = (0, 3)

B = (0, 2)

C = (1, 0)

D = (3, 0)

The longest side  is   AD  =

sqrt  [ 3^2 + 3^2 ]  =

sqrt [ 18]  =

3sqrt ( 2)

Guest "Exactly one of the axioms of a vector space is not satisfied"

Witch is this axiom? 

Rom yes im sure the exercise say it's not.For this reason i can't solve the exercise

PLEASE HELP!!!

The points  (0, 0)  and (3, - 2)  are on the graph

The slope  is   [  -2 - 0 ] / [ 3 - 0 ]   = -2/3

So....the equation of the line is

y =  (-2/3)x     mutiply through by 3

3y = - 2x       add 2x to both sides

2x + 3y  =  0

To find the x intercept.....let y  = 0   and we have

3x - 5(0)   =  7

3x  =  7       divide both sides by 

x  =   7/3   ⇒    x intercept

Go to this MAA site and find out how they count all 293 ways:

https://www.maa.org/frank-morgans-math-chat-293-ways-to-make-change-for-a-dollar

Yeah.....this is definitely a tough thing to learn....!!!!

Again....see here :

https://web2.0calc.com/questions/algebra-problem-2-probs

i'm not great at word problems but im trying my best to succeed.

See here, Leaded :

https://web2.0calc.com/questions/algebra-problem-2-probs

Anytime an angle inscribed in a circle intercepts a diameter  [ in this case, AC ], its measure  = 90°

So    ABC  = 

"90 degrees"    

You will NEVER know who I am.... TO BE CONTINUED.

Standard form is  Ax + By  = C

y = (4/5)x - (7/10)

Multiply through by 10 to clear the fractions

10y  =  8x  - 7       subtract 10y from both sides, add 7 to both sides

7 =  8x  - 10y

8x - 10 y   =  7

Let the amount that Anna canned  = A

And John canned 4A

So

4A  = 24       divide both sides by 4

A  =   6   [ qts]