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Smoking  

9.00 x   [ 75000 / 25000] x 12   =  $324

Non-Smoking

5.50  x   [ 75000 /  25000 ] x 12    = $198

Can  you take it from here, NSS ???

Here's a simple formula for this, NSS

Applicable Category Price x     [ Amt of Requested Coverage / 25000]

So...in this case....we have

6.75   x     [ 125000/25000]  =  $33.75

Remember that this is the monthly premium.....if they want yearly, we need to multiply the answer by 12....

a    you are given the position function

b     velocity function is the derivative of position fxn

c         time will be when s(t) = 0

d       When you have THAT time , substitute that value of 't' in to the velocity function from 'b'

Her probability of dying is  1958.7 / 100000

So...the probability of her living   is

1  -  probability of dying   =

1 - 1958.7 / 100000   ≈  .98

Yah....I had cal 1    cal 2   cal 3    Diffy q   Advanced Applied Math....but it was 35 years ago, with no practice since....

    BUT  I get to re-learn a bit here.....!

Dang....Quasi-almost-so-close !

HAHAHA!!!!!....don't feel bad.....I took 4 semesters of Calculus and can barely do a derivative, now   !!!!

 Use it... or Lose It.......!!!!

YOU WIN !!!!!!!     Haha ...so ABSOLUTELY true !    I am still laughing !!

A long time ago for me too, EP....LOL!!

1 False.....the function   y = abs (x)  is continuous, but not differentiable at x = 0

2 True....Remember the motto..."Differentability implies Continuity....but Continuity does not imply Differentiability "

3 Just as EP said

4  Remember that we can take as many non-zero derivatives of a polynomial as its degree

For instance  x^2   ⇒  2x  ⇒ 2   ⇒ 0    [ two non-zero derivatives ]

So....just as EP said !!!

5  sin x   ⇒ cos x ⇒ - sin x ⇒ - cos x  ⇒ sin x    ..... true   !!!!

Yikes....thanx Chris !

Egad.....that was a long time ago

I THINK:

1 is true

2  not true (I think)

3 Nope  ....FIRST derivative of position is VELOCITY....second is ACCELERATION

4 I THINK so....it would be the derivative of a constant...=0

5 I believe that is true

This is known as the "Chain Rule"

d/dx   [ f(x) }^n   =

n * [ f(x)] ^(n - 1) * [ f ' (x) ]

Where f ' x   is the derivative of f(x)

Hmmmm     not sure...        n f(x)^(n-1)   ???

I just keyed in the points and let the website generate the graph [ and function ] based on that.....it's probably pretty similar to what you would do in Desmos...but.....I'm not sure

f(x)  =  x^2 - 2

This is the parent graph  y = x^2   just shifted down 2 units

So....A

(x) = - ( x - 2)^2

This is the parent graph  "flipped" over the x axis  and shited to the right by 2 units

So...C

f(x)  = x^2 - 2x

This turns upward.......it's easier to see if we write it this way

f(x) = x ( x - 2)

This has "zeros"  at x = 0  and x = 2

So....it turns upward and crosses the x axis at  x = 0 and x = 2

So...B

f(x)  = -x^2 + 2x

If we write this as   f(x)  =   - (x^2 - 2x).....it's the same graph as B  "flipped over" the x axis

So.....D

Hope that helps   !!!

She is making MONTHLY payments, so you have to look at the MONTHLY interest

  .03 / 12 = .0025    is the 'r' in the equation     AND 'n' will be the number of MONTHS

     n= 10 yrs  x  12 mos/yr = 120 periods

   = 95 (1+ .0025)^120 -1)/.0025 = $ 13275.43

They let us to desmos calcualtor that's why..  so do you know how you can explain how you got the answer or you just put it in to graph

Cruise on... !

That's the quadratic regression for the data

You will probably have to use some sort of technology for these, NSS....I think there is a way to "hand" calculate the function, but it's probably tedious.......

I don't think that your teacher would expect you to do that.......technology is DEFINITELY the way to go, here !!!

The ^2 kinda daunted me, I understand it now! Thanks :D

Is y = .27x^2 -2.44x +7.49 explaining on how you got your answer? Or is that the quadratic regression for the data..?

h(x)= y   for the table....just substitute the value of 'x' in to the equation to find the 'y' value for the table

Example   x = 0

     h(x) = y = -0.001(0)^2 + 0 =    0

     h(x) = y = -0.001(200)^2 + 200 = 160

Fill in the rest of the table the same way and you will find the highest value (given the values of x that you have in the table)

   Post back if you need more help.....

y = (-2+x)((x+3)

      (x-2)(x+3)

       x^2 +x -6

y= (-x+2)(5-x) - 2x^2

  = -5x +x^2 +10 -2x -2x^2

   = -x^2 - 7x +10

Big shout out to Dimitristhym for answering my questions, but how do you write the answer to number 2) in regular form? I can't get the x_> 8 things right. Thank you all, though!

Thank you, CPhill!