In rectangle ABCD, we have A=(6,-22), B=(2006,178) , and D=(8,y), for some integer y. What is the area of rectangle ABCD?
The slope from A to B is [ 178 - -22] / [ 2006 - 6 ] = 200/ 2000 = 1/10
So...the slope between A and D will have a negative reciprocal slope....so we have
[ y - - 22 ] / [ 8 - 6 ] = -10
[ y + 22] [ 2] = -10
y + 22 = -20
y = -2
So D = (8, - 2)
And the distance from A to B = sqrt [ (2006 - 6)^2 + (-22 - 178)^2 ] = sqrt [ 2000^2 + 200^2 ] = sqrt (4040000)
And the distance from A to D is sqrt [ (8 - 6)^2 + (-22 - - 2)^2 ] = sqrt [ (4 + 400] = sqrt (404)
So....the area of ABCD = sqrt (4040000)*sqrt (404) = sqrt (404000 * 404 ) = 40,400 units^2