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thanks again

Ohhh I see. Your answers r going by only x values. I thought your answers included y values in the intervals also.

Your help is very appreciated! Thank you for taking the time to help.

Thank you very much for your help and work, especially the thorough solution!

i would assume so

Thank you very much!

i don't think i made a mistake there.... check the graph again....

you can use a calculator to check, you know

ok, no need to say it's due tmrw, cuz this is an aops thing

the solution:

Let's say that the radius is equal to r. Let's say the midpoint of CD is P. Then, we know that PC= 9. Draw OP, and notice that OP is perpendicular to CD. Also, since $\angle ABD$ = 90, that means that AOPB is a rectangle, which implies AB=OP= 12. Using the pythagorean theorem, the radius is equal to $\sqrt{9^2 + 12^2}, \text{which is equal to } \boxed{15}$. Just use pi r ^2 to find the area, which is 225 pi

So for e., would the graph be constant over the interval of (-∞, -7)? I thought maybe you made a mistake there ;)

Because there are only two teams, Alice and Andrew are on opposite teams. Now, we can choose 3 people out of the other 6 to be on Alice's team, and the other 3 to be on Andrew's. So, the answer is 6C3 = 6! / (3!)^2 = 720 / 36 = 20.

7. arcsin 7/15 = 27.818

8. arccos 8/25 = 57.769

thanks,

24789.4 km / 43.5 km = 569.871 km  marked incorrect, is the answer they are looking for 5.69.8 km to match the sig figs in the question?

1. We can see if it is arithmetic or geometric. Obviously it is not arithmetic because 9 - 4 is not 4 - 1, and it is not geometric because 9/4 is not 4/1 = 4. So, the answer is Neither.

2. Let's first see if it is arithmetic. We can see that 20 - 18.5 is 1.5, so it goes down by 1.5. The next term also goes down by 1.5, and so on. So, this is an arithmetic sequence.

3. For this one, we can tell it is not geometric because 10/9 is not 9/8. If it was arithmetic, the positive number would've be negative or vice versa. So, this is Neither.

5. This is not geometric because 10/8 is not 8/5. Also, this is close to being arithmetic, but 10 - 8 is not 8 - 5, so it is neither.

a. when x = (-6, -3) and (3,13)

b. when x = ($-\infty$, -6) and (-3,3)

c. when x= (0,4) and (-8, -4)

d. when x = (4,13) and (-4,0)

e. when x =($-\infty$,-8)

f.the domain is when x = ($-\infty$,13) and the range is when y = (-9,7)

asdf335, the 2nd answer was actually 2144. :)

But I appreciate the help!

1)

All we have to do is add the coefficients of the x^3 terms, or 1 + 5 = 6.

2) 

Because a is a constant, the largest possible must be 4, as a cannot change the degree.

3)

We want to have the smallest possible degree, so we should cancel terms. So, we set b = -1/2 and the degree of the sum is 1.

4)

To find the degree of the porduct, we just add the degrees of the functions. So, our answer is 4 + 4 = 8.

5)

We can find which terms multiply to get something with x^2 in it. We get 28 + 2t - 5 = 0, or 23 + 2t = 0 => t = -11.5.

Hoping this helped,

asdf334

1. Undefined, as 0^0 is still being debated. Otherwise, it would be geometric, because it is the sequence 0^0, 1^1, 2^2, 3^3

2. This is an arithmetic sequence because each term decreases by 1.5.

3. Neither, as this can be recursively defined as something with even/odd cases.

5. I think neither, as it each term decreases by n+1

Can you provide the intervals as coordinates with parenthesis? For example an interval of (-2,0)

nonzero digits are significant, so it would be 20cm and 506.7cm

a. The positive parts are -6

b. The negative parts are -3

c.It is increasing at -8

d. decreasing at 4

e. The constant part is x<-6

f.The domain of the function is x<=13. The range of the function is -9<=y<=7.

I believe Rom is correct

a. The graph is positive when it is above the y-axis; if you can see, it is positive from (-6, -4) and (3, 13).

b. So? Can you find the negative using this method?

You are very welcome!

:P

∑[(2n - 1), n, 1, 15] = 225

huh... turns out the answer is 106

I'll have to look at this one.