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i make a new one so text there 

I think its A or B but im not sure 

Solve for x:
log(x) (2 - log(x)/log(4)) = log(π)

Expand out terms of the left hand side:
2 log(x) - (log^2(x))/log(4) = log(π)

Multiply both sides by -log(4):
log^2(x) - 2 log(4) log(x) = -log(4) log(π)

Add log^2(4) to both sides:
log^2(4) - 2 log(4) log(x) + log^2(x) = log^2(4) - log(4) log(π)

Write the left hand side as a square:
(log(x) - log(4))^2 = log^2(4) - log(4) log(π)

Take the square root of both sides:
log(x) - log(4) = sqrt(log^2(4) - log(4) log(π)) or log(x) - log(4) = -sqrt(log^2(4) - log(4) log(π))

Add log(4) to both sides:
log(x) = log(4) + sqrt(log^2(4) - log(4) log(π)) or log(x) - log(4) = -sqrt(log^2(4) - log(4) log(π))

Cancel logarithms by taking exp of both sides:
x = 4 e^sqrt(log^2(4) - log(4) log(π)) or log(x) - log(4) = -sqrt(log^2(4) - log(4) log(π))

Add log(4) to both sides:
x = 4 e^sqrt(log^2(4) - log(4) log(π)) or log(x) = log(4) - sqrt(log(4)^2 - log(4) log(π))

Cancel logarithms by taking exp of both sides:

x = 4 e^sqrt(log^2(4) - log(4) log(π))= 2.24253438346688
or x = 4 e^(-sqrt(log^2(4) - log(4) log(π)))= 7.13478469626164
2.24253438346688 x 7.13478469626164 = 16

im good in math I just can't do all 1 Trigonometry so a=1 b=1 c=1 can do that so i ask this question.

wiether your intention was to be mean or not, it did sound mean mate.

don't be mean I nice and this is for math it to help me in Trigonometry it has all ones 

never mind i good now 

Like, 2. Wood chucks aren't very strong creatures, though given time to train, I imagine it can easily bump that number to a 7.

something just does not seem right like how we say 1-1=0 can there be no 0 we never yous it.

I know but 1 = the same thing. I just makeing sure. 

Find the distance between Q = (3, -7, -1) and the line through A = (1, 1, 2) and B = (2, 3, 4)

WHAT solution?

Wikepedia states this about solubility in WATER

Solubility in water

anhydrous:[1] 84.03 g/100 mL (0 °C)
334.9 g/100 mL (90 °C) soluble (anhydrous)

Find the TOTAL area of the rectangle =  H x W =  14 x 10 m^2

    Subtract the triangle area   1/2 b x h = 1/2  x 3 x 8

    Subtract the trapezium area    (5+7)/2  x 10              To find the answer for the area of the lawn....

Fin the product of all real solutions to    \(x^{2 - \log_4(x)} = \pi\)

This turned out to be a really cool question!! 

\(x^{2 - \log_4(x)} = \pi\\ log_4[x^{2 - \log_4(x)} ]=log_4[ \pi]\\ (2 - \log_4x) log_4x=log_4 \pi\\ 2log_4x - (\log_4x)^2=log_4 \pi\\ (\log_4x)^2-2(log_4x)+log_4 \pi=0\\ Let A=log_4x\\ A^2-2A+log_4\pi=0\\ A=\frac{2\pm\sqrt{4-4log_4\pi}}{2}\\ A=1\pm\sqrt{1-log_4\pi}\\ sub\; back\;again\\ log_4x=1\pm\sqrt{1-log_4\pi}\\ 4^{log_4x}=4^{1\pm\sqrt{1-log_4\pi}}\\ x=4^{1\pm\sqrt{1-log_4\pi}}\\~\\ \text{So the product of the only two values of x that make this true is}\\ 4^{1+\sqrt{1-log_4\pi}}\times 4^{1-\sqrt{1-log_4\pi}}\\ =4^{1+\sqrt{1-log_4\pi}+1-\sqrt{1-log_4\pi}}\\ =4^2\\ =16 \)

I could not work out anything any more useful either.

Here are the 2 points on the graph

Oh!!got it! Thank you!!

ABCD is an isoscles trapezium in which AD // BC, if BC=2AD=20cm and its area is 180, find the length of each of its legs. 

Mathematica 11 Home Edition gives the following 2 real values for x with no explanation!!

x =2.2425  and   x =7.1348

2.2425 x 7.1348    =~ 16

\(\text{Let's treat the dice as distinct}\\ \text{# rolls consisting of 123456} = 6!\\ \text{total # of possible rolls } = 6^6\\ P[\text{roll of 6 distinct digits}] = \dfrac{6!}{6^6} = \dfrac{5}{324}\)