First one....see the image below :
Let A = (0,0)
Let C = (10,0)
And we can find B, thusly
Construct a circle with radius 9 centered at the origin
The equation of this circle will be x^2 + y^2 = 81 (1)
And construct a circle wilth radius 17 centered at (10, 0)
The equation of this circle will be (x - 10)^2 + y^2 = 289 (2)
We can find the coordinates for point B, thusly :
Subtract (1) from (2) and we have that
(x-10)^2 - x^2 = 208 simplify
x^2 - 20x + 100 - x^2 = 208
-20x = 108
x = -108/20 = -5.4 = x coordinate of B
And taking the positive value for y, we have that
(-5.4)^2 + y^2 = 81
y^2 = 81 - 29.16
y = 7.2 = y coordinate of B
So....B = (-5.4, 7.2)
And AX is the bisector of angle A
So....we have the following relationship
AC/AB = XC /XB
10/9 = XC / XB
Then BC has 19 equal parts and XC is 10 of them.....so XC = (10/19)*17 = 170/19
So....using a similar triangle idea.....
Distance from B to the x axis / BC = XY / XC
7.2 / 17 = XY / (170/19)
(170/19) * 7.2 /17 = XY = (170/17)(7.2 / 19) = 10 * 7.2 / 19 = 72 / 19