Hello Melody: I wrote a very short code to convert 2012! to base 43 in its entirety: Here are just the beginnings of the number and its trailing zeros. They count to 47 zeros.
n=2012!;m=43; a=n%m;printa,", ",;b=int(n/m);n=b;if(n>m, goto2, discard=0;printb,
(6, 38, 32, 10, 35............ 14, 21, 18, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0)
P.S. I also converted it to base 47 and it gives 42 zeros.