oh you just edited it.
gotcha
But if you divide by 3, you get 1/3
I forgot to add 2x2 to BOTH sides.
don't worry, its fixed. The solution should be correct.
That took me long. Phew.
Wait- What?
fixed it.
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Fixed
Working off of \(3x^2=x^4+1\)
We add 2x2 to both sides
\(3x^2+2x^2=x^4+2x^2+1\)
Factor
\(5x^2=(x^2+1)^2\)
Divide both sides by \((x^2+1)^2\)
We get:
\(\frac{5x^2}{(x^2+1)^2}=1\)
Divide both sides by 5.
and you get your answer of \(\boxed{\frac{1}{5}}\)
k = 1/4
a_17 = -5
x_2012 = a + 1/b
c = 2 sqrt(5)
(a,b) = (2,-1)
Oh.
But where's the question?
eh?
Wha is that supposed to be?
Sorry I just edited it....
It's equal to 3!
You sure you typed that correctly?
What do you mean by
"If \(x^2+\frac{1}{x^2}\)"
Is it equal to something..?
Angle AYX = 144.
EP proved that there is nothing wrong with picture posting.
OhHHhhhhHHHHHhhhhhhhhhHhhhhh
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both j & k are positive integers
The question says that j and k have to be positive.
This is why it doesn't work, becuase when you add three to both sides, j and k become 0.
0 is neither positive or negative. So 0 is not a solution
Undefined?
:|.....
Ginger, you never disappoint!
You are a Troll with tremendous talents in mathematics and proctology. After reaming out the asshoIes, you burn them a new one.
ROFLAMO! I’m going to stroke!
I think I can....Yeppppp....Just try it again....
