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Yes i can thank you very much. 

We want the discriminant to be negative, so we want

b² - 4(1)(9)  <  0

b² - 36  <  0

b²  <  36

This is true when...

| b |  <  6

Which is true when...

b < 6     and     b > -6

So  b  is any number in the interval  (-6, 6)

(The endpoints are not included because that makes the discriminant equal to zero, which gives only one real root to the original polynonmial.)

We want b^2 <= 9, so the answer is [-3,3].

I don't know if this will help, but you could watch this video!

g(x)  =  -2x² + 3x

                                        Replace every  x  with  -3

g(-3)  =  -2(-3)² + 3(-3)

                                        Evaluate the right side of the equation.

g(-3)  =  -2(9) - 9

Can you finish it from here?

https://web2.0calc.com/questions/help_17627 

its a circle!

people who like math are slightly above average in math.

If you were going to take statistics in college I would highly encourage you to take it in high school so that you would be more prepared for the college level class. But since you aren't going to college, then maybe don't take it.

(For me, statistics was pretty difficult in college. I think I found it so difficult because I never took it in high school. Whereas I found all my calculus classes not so difficult in college, and I do think that is in part due to the fact that I took calculus in high school. But of course I can't speak for everyone - I'm sure other people would find calculus much more difficult than statistics regardless of previous experience.) Tl;dr: College-level statistics is difficult for me, but that could be just be me.

Do you have to take a math class your senior year? What other options are there?

There may be an easier way to do this, but I would just go through the multiples and find them.

12, 15, 18, 21, 51, 81, 102, 105, 108, 111

114, 117, 120, 123, 126, 129, 132, 135, 138, 141

144, 147, 150, 153, 156, 159, 162, 165, 168, 171

174, 177, 180, 183, 186, 189, 192, 195, 198, 201

210, 213, 216, 219, 231, 261, 291, 312, 315, 318.

Thanks, Gadfly....I like that approach  !!!

Check this out: https://web2.0calc.com/questions/c-2-0c-c_6

This will explain everything (hopefully) you need to know!

Welcome!

Well, there are many values.

Me too!

Set up the equation

\(8-\frac{4}{5}f>-14-2f\)

Now solve for f.

\(22>-\frac{6}{5}f\)

\(-\frac{55}{3}

Or for interval notation, \((-\frac{55}{3}, \infty)\)

You are very welcome!

:P

I'm not sure what you're trying to ask. Are you looking for a graph of the function?

This will produce a cone   one leg will be the height ...the other will be the radius

Volume of a cone = pi r^2 h/3     r^2 is more determining factor of final volume than h....  you can see that the larger radius ^2    will produce the larger cone  ....rotate around the 3 leg (h)

pi 4^2  3 /3 = 16 pi =~50 cm³

How good are you at math?

x = large systems

135-x = small systems

235 x  = cash from large systems

185 (135-x)  = cash from small systems

Added together the cash = 27225 for the month

235 x   + (185 )(135-x) = 27225     solve for x (the number of large systems)    then small systems = 135 - x  

8- 4/5 f > -14 - 2f     subtract 8 from both sides

- 4/5 f > -22 -2f          add 2f to both sides

 6/5 f >  -22                 multiply both sides by 5/6

f  > - 110/6

f > - 55/3

The largest area would be of an equilateral triangle. But, since 20 cannot be divided into 3 equal integers, then the closest would be a triangle with sides =7, 7, 6, which would have an area =18.974 compared to an equilateral triangle with sides=20/3 =6 2/3, which would have an area =19.247.

Hello, Charley!

Web2.0Calc is a site dedicated to helping people understand and appreciate all forms of mathematics. The forums are a place for people to ask questions about parts of math they don't understand, whether it's a specific question or a short explanation of a whole part of math. If you have any other questions, feel free to ask!

Happy to welcome you to the family,

Daewei

I think the Moderator's have to tag an answer with the "Best Answer"  logo.....