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I am sorry. I make a mistake.

Hence, 

First multiply 

(q+4)(p+3) 

then multiply

(q+2)(p+1) 

Subtract them and solve the equation 

Solution:
 

(q+4)(p+3)=qp+3q+4p+12

(q+2)(p+1)=qp+q+2p+2 

Subtract

qp+3q+4p+12-(qp+q+2p+2)

qp+3q+4p+12-qp-q-2p-2

2q+2p+10=44  subtract 10

2q+2p=34

Divide by 2 

q+p=17

It appears he does answer some questions for himself. Not math questions, though. 

Actually i solved it and got 5 : they would be 2,3,7,1, and lastly -1.

At least you question is readable since you edited it.

It wasn't readable when it was answered LOL.

Do you ever do any questions for yourself?

Just factorize the top and the bottom then cancel.

maybe 13.

I äm going with 13, that is till I change my mind again.

The answer is 10.

The answer is 15.

We will not help you cheat on homework problems.

THANK YOU

Taking x = y = 0, you get 2f(0) = f(0), so f(0) = 0.

Taking y = 0, you get f(x) + f(0) = f(0) = 0, so f(x) = 0.

So the only function is f(x) = 0, and n*s = 1*0 = 0.

1. If F_1 and F_2 are the foci, then PF_1 - PF_2 = 10, so the distance from P to the other focus is 17.

I think the answer is 3.

I think 12 ... 

 \(2^x=72y\)                 where x and y are integers.

I don't think there is one....

\(72=9*8=2^3+3^2 \)

\(2^x=72y \)

the prime factors on the left side is just 2 and on the right side it is 2 and 3

I do not think any integer answers are possible.....                                                                                                                          

You can see straight off that x cannot be 2 or 6.

Now just for the moment you can ignore that.

Try solving for x in terms of k and see what happens.   The answer will present itself.

No one answer over me please. 

But asker guest can interact with me if he/she wants      (or with others if i don't answer quickly)

1. AE = 4*4*4/(6*6) = 16/9

2. Using coordinates, we can let O = (0,0), X = (x,0), Y = (0,y).  Then A = (-x,0) and B = (-0,y), so x = 6 and y = 2*sqrt(13).  Then OZ = sqrt(6^2 + (2*sqrt(13))^2) = 2*sqrt(22), so CZ = 4*sqrt(22).