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16 or 17 i believe

Note that z^2 + 4 = (z + 2i)(z - 2i), so we can write the given equation as |z + 2i||z - 2i| = |z||z + 2i|. If |z + 2i| = 0, then z = -2i, in which case |z + i| = |-i| = 1. Otherwise |z + 2i| /= 0, so we can divide both sides by |z + 2i|, to get |z - 2i| = |z|. This condition states that z is equidistant from the origin and 2i in the complex plane. Thus, z must lie on the perpendicular bisector of these complex numbers, which is the set of complex numbers where the imaginary part is 1. In other words z = x + i for some real number i. Then |z + i| = |x + 2i| = sqrt(x^2 + 4) >= 2. Therefore, the smallest possible value of |z + i| is 1, which occurs for z = -2i.

n is 9

Let's think of the extreme.

What if I took 5 black and 5 white socks out? Then the next sock to take out would have to make a pair.

So 5+5+1 = 11.

2A(b^2)

This is an original question.

All DERFs are ENAJs. One-third of all ENAJs are DERFs. Half of all SIVADs are ENAJs. One SIVAD is a DERF. Eight SIVADs are ENAJs. There are 90 ENAJs. Draw the Venn diagram. How many ENAJs are neither DERFs nor SIVADs?

Yes. This is the whole question.

4503 mod 11 = 4 pieces that the cook gets.

The answer is A, D.

There are 6 pairs of congruent triangles.

4503 mod 11 = 4 pieces to the cook.

Do your own homework.

The remainder is 6.

The number of such rectangles is 88.

The smallest such positive integer k is 4.

You can make 10 noncongruent figures this way.

You can take f(z) = 3z + 4 - i.

You are a cheater.  Do your own homework.

The area of PQR is 9.