All Questions ⁺⁰238062 Questions

0

728

1

Please help thanks!

Let f(x) = log_b x, and let g(x) = x^2 - 4x + 4. given that f(g(x)) = g(f(x)) = 0 has exactly one solution and that b > 1, compute b.

Guest Jul 19, 2019

0

995

2

What is c?

Let f(x) = (x+2)^2-5. If the domain of f is all real numbers, then f does not have an inverse function, but if we restrict the domain of f to an interval [c,infinity), then f may have an inverse function. What is the smallest value of c we can use here, read more ..

Guest Jul 19, 2019

0

732

1

Help please

Let S be the set of all real numbers a such that the function {x^2+5x+a}/{x^2 + 7x - 44}can be expressed as a quotient of two linear functions. What is the sum of the elements of S?

Guest Jul 19, 2019

0

982

1

Help please

Guest Jul 19, 2019

0

559

1

Help me please

Guest Jul 19, 2019

0

2190

1

Mathcounts/AMC8

John noticed that the angle formed by the minute hand and hour hand on a standard 12-hour clock was 110 degrees when he left home after 6 p.m.; it was also 110 degrees when he returned before 7 p.m. that same night. If he left home for more than five minutes, read more ..

Guest Jul 19, 2019

0

2899

2

Please Help!

Yesterday, Teddy played a game repeatedly on his computer and won exactly 85% of the games he played. Today, Teddy played the same game repeatedly, winning every game he played, until his overall winning percentage for yesterday and today was exactly 94%. read more ..

Guest Jul 19, 2019

0

2451

1

HELLLLLPPPPP! due 2moro

Find the sum of all the integer values of $m$ that make the following equation true: $\left(2^m3^5\right)^m 9^7=\dfrac{\left(256\cdot3^m\right)^m}{\left(\sqrt2\right)^{14}}$.

Guest Jul 19, 2019

0

1146

1

HELPPPPP!

Suppose $f(x)=x+1$. For what value of $x$ is $\overbrace{f(f(\cdots(f}^\text{2015 total \textit{f}s}(x))\cdots)=0$?

Guest Jul 19, 2019

0

2137

1

Help Please!

The sum of three consecutive positive integers is a perfect cube. Find the least possible value of the smallest number, assuming that the middle number ends in at least 5 zeros.

Guest Jul 19, 2019

0

936

3

Help me please

Find the sum of all integral values of with for which the equation has two rational roots.

Guest Jul 19, 2019

0

1

2793

8

+19

Can someone help me with this math question and show me how to do it?

A company's revenue from selling x units of a new software game is R(x)=1000x-20x^2 dollars. if sales are increasing at a rate of 50 units per day, find how fast the revenue is growing at a time when 20 units have been sold.

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demandingwaffle Jul 19, 2019

0

993

3

Help please

Guest Jul 19, 2019

0

890

3

Question, help me

Guest Jul 19, 2019

+1

546

0

Help please urgent

Show that if x, y, and z are integers such that x^3 + 5y^3 = 25z^3, then x=y=z=0.

Guest Jul 19, 2019

Jul 18, 2019

0

948

1

Help me please

Guest Jul 18, 2019

0

847

1

Can you help me walk through this?

x^(5)-3x^(2)+12x-1=a(x^(2))(x^(2)+x+1)(x^(2)+2)^(3)+Bx(x^(2)+x+1)(x^(2)+2)^(3)+c(x^(2)+x+1)(x^(2)+2)^(3)+(Dx+E)(x^(3))(x^(2)+2)+(Fx+G)x^(3)(x^(2)+x+1)(x^(2)+2)^(2)+(Hx+I)x^(3)(x^(2)+x+1)(x^(2)+2)+(Jx+K)x^(3)(x^(2)+x+1)

Guest Jul 18, 2019

0

1043

2

Help please

A ''super ball'' is dropped from a window 16 meters above the ground. On each bounce it rises the distance of the preceding high point. The ball is caught when it reached the high point after hitting the ground for the third time. To the nearest read more ..

Guest Jul 18, 2019

0

903

1

Help me please

Guest Jul 18, 2019

0

1522

5

Halp pls

Determine the smallest positive integer such that 60^n+k*71^n is divisible by 1441 for all odd positive integers n

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Guest Jul 18, 2019

0

796

1

+541

Question

Given that p is greater or equal to 7 and is a prime number, evaluate

xXxTenTacion Jul 18, 2019

0

1488

1

+541

Help me

Let p be the largest prime with 2010 digits. What is the smallest positive integer k such that p^2-k is divisible by 12?

xXxTenTacion Jul 18, 2019

0

853

3

help, thanks!

Guest Jul 18, 2019

0

823

1

help please

Guest Jul 18, 2019

0

787

1

help me

Guest Jul 18, 2019

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