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8n4−5/ 6n4+7

As n becomes larger and larger, the nth term converges to:

8n4−5/ 6n4+7 = 1 1/3

When you use capital letters on the internet it is interpreted as you screaming at people.

Which is quite impolite.

Plus why have you not thanked danne9000 or commented on the answer?

It seems you are the one who is failing to communicate.

An amusement park charges admission plus a fee for each ride. Admission plus two rides costs $10. Admission plus five rides cost $16. What is the charge for admission and the cost of a ride?

A  =  cost of admission

R  =  cost of one ride

                                                A + 2R  =  10     (1)   

                                                A + 5R  =  16     (2)    

subtract (1) from (2)                       3R  =   6

divide both sides by 3                       R  =   2              cost of one ride is $2

plug value of R into (1)             A + (2)(2)  =  10

                                                  A + 4  =  10                  

subtract 4 from both sides                A  =   6               cost of admission is $6  

_.

Thank you, Omi and heureka!

The mean of a data set is found by finding the sum of all the values and dividing by the number of values.

Therefore, the sum of all the values must be the mean times the number of values.

Since the mean is 5 and there are 9 values, the sum of these numbers must be 5 x 9 or 45.

When a tenth value is added and the means becomes 6, the sum of these numbers must be 6 x 10 or 60.

Therefore, the tenth value must be 60 - 45 or 15.

Let  t₁ = first term                   --->     t₁  =  -12

Let d = common difference     --->     d  =  7

Let n = number of terms         --->     n  =  30

Let t _n = n^th term                     --->     t_n  =  t₁ + (n - 1)·d     --->     t₃₀  =  -12 + (30 - 1)·7     --->     t₃₀  =  191

Let S = sum of the terms        --->     S  =  n(t₁ + t_n)/2     --->     S  =  30(-12 + 191)/2     --->     S  =  your answer

If there is a fraction bar between the "i² +i" term and the "2", then what you have is:

(5² + 5)/2  + (6² + 6)/2 + (7² + 7)/2 + (8² + 8)/2 + (9² + 9)/2 + (10² + 10)/2 + (11² + 11)/2 + (12² + 12)/2

Now, it's between you and your calculator ...

50 cm  =  1.64 feet 

_.

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The total minus the fraction sold in the first hour and the remaining fraction after the shift gives you the second hours sales.

I.e. 15/15-(3/15+6/15) => 15/15-9/15=6/15

6/15 sold in the second hour.

 

Just multiply each term by the common ratio of 6/10:

125/9, 25/3, 5, 3, 9/5, 27/25, 81/125, 243/625, 729/3125, 263/1879........etc.

trig help

YES YOU ARE

You'll want to express the number of students in each of the periods as a function of the number of students in a reference period.

Let x be first period, y second periodand z third period

We know what y=2x and z=3x-10

 and x+y+z=158 

Which you can then rewrite as a function of X 

x+2x+3x-10=158

6x-10=158

6x=158+10

x=168/6

x=28

y=2*28

z=28*3-10

So first semester 28 students, second semester 56 students and third semester 74 students.

Cheers

A box is 50 cm long. Which of these is closest to the length of this box in feet? (1 inch = 2.54 cm)

 1.02 feet 

1.17 feet 

1.64 feet 

4.15 feet

Correct

SO 50

50 holes in 25 minutes is the answer. 

Cheers

WHTS ANSER

First find the number of holes per drilled per minute which is 12/6=2
So 2 holes per minute times 25 minutes gives us 50 holes. 

Cheers

First find the number of holes per drilled per minute which is 12/6=2
So 2 holes per minute times 25 minutes gives up 50 holes. 

Cheers