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That's wrong.

A bakery offers a sale price of $2.50 for 3 muffins. What is the price per dozen?  

Take those 12 muffins (the dozen) and divide them into four groups of three.

Each of those groups of three muffins goes for $2.50.

So, four groups, times $2.50 per group, makes the total price $10.00

_.

     4² + 3² = 5²    

     So, it's 3" tall.     

_.

\(91\times 10-695=215,\text{ }\frac{215}{5}=\boxed{43}\)

43 is the answer

p = i, q = 1 + i, and r = -1 - i, so p^2 + q^2 + r^2 = 4i - 1.

On a farm the number of cows and the number of sheep are in the tatio 6:5 the number of sheep and the number of pigs are in the ratio 2:1 the total number is 189 how many sheep are there on the farm?

The sixth term:  -8100 x (-0.1)⁵  =  answer

If  x  represents the number of pounds of cabbage and  y  represents the price in dollars,

then  (5, 2)  means that  5  pounds of cabbage costs  $2.00.

If that is true, then  1  pound of cabbage will cost  $0.40.     (divide both values by 5)

The ordered pair  (10, 4)  means that  10  pounds of cabbage cost  $4.00.

I'm not sure what it means to "use benchmarks"; but:

2¹  =  2

2²  =  4     --->     log₂4  =  2

2³  =  8     --->     log₂8  =  3

So:  log₂6.5  is somewhere between  2  and  3; I would guess that it's about 2.5.

Selena's snow cone stand sells small snow cones for $2 and large snow cones for $3.50. One summer day, she sold $163 worth of snow cones. If the number of large snow cones was 12 more than the number of smalls, how many of each size did she sell?

Farah has been saving part of her allowance in a bag every month. The bag containing $2 and $10 notes had a total value of $1068. 6 pieces of $10 notes were exchanged for $2 notes of the same value. In the end, the number of $10 notes was the same as the $2 notes. How many $2 notes were there at first?

To solve this you have to express the quantities of both as a function of one. For example since the number of bouquets sold was 15 more than the number of hearts, you can express the bouquets as X and then the number of hearts as X-15 rather just Y.

Then you have the following equation.

X*5+(x-15)*3=339

Factor it out to get

5x+3x-45=339

8x=339+45

x=384/8

x=48

y=48-15

y=33

Check it's right by plugging these numbers into the formuler 5x+3y=339

5*48+3*33=339

So they sold 48 roses and 33 hearts. 

Cheers

A bakery offers a sale price of $2.50 for 3 muffins. What is the price per dozen?

$2.50 / 3 =$0.83 cents per muffin

12 x 0.83 =$10 for a dozen muffins.

Cows / sheep =6 / 5.......................(1)
Sheep / pigs   =2 / 1.......................(2)
Cows + Sheep + Pigs =189............(3)

Use substitutions to get:
Cows =84,  Sheep =70,   Pigs =35

You can factor a^4 + 4 as (a^2 - a + 2)(a^2 + a + 2).

∑[ 4^(n - 4), n, 1, ∞ ] =?

\(100-75=25\) 

  x    -   9     =     3  "25% was the discount and you saved 3, which means the discount was 3 dollars, then you can find the paid (After the discount by cross multiplication i.e. 3*75/25 will give you 9) 

thus x=12 

3 is 25% of 12 

So you can learn how to count, groupings, multiply, divide, add, subtract, etc....

This is not the question where you posting this right now. this is for math problems and word problems.

The common ratio r is \(-\frac{2}{3}\) How is it found? ----> \(\frac{a_2}{a_1}\) Since it is a geometric series.

This series is a finite (I.e. you just want the sum of the first 8 terms) 

There is a formula for it which is:

\(S_n=\frac{a_1(1-r^n)}{1-r}\) , of course "r" can't be equal to 1

The first term we have is 120, common ratio is \(-\frac{2}{3}\) (r) and we want the sum of the first 8 terms so just substituting them will give you the answer.

\(\frac{120*(1-(-2/3)^8}{1-(-2/3)}\) Just simplify it. 

A rectangular garden has a length that is 16 meters and width of 12 meters .the owner of the garden is adding a walkway around the garden and wants the walkway tl be of uniform width. If the total area of the garden and walkway can cover 285 square meters, what is the width of the walkway ?

Hello Guest!

\((16+2x)\times (12+2x)=285\\ 192+32x+24x+4x^2=285\\ 4x^2+56x-93=0\)

\(x = {-b \pm \sqrt{b^2-4ac} \over 2a}\)

\(x = {-56 \pm \sqrt{56^2+4\cdot 4\cdot93} \over 8}\)

\(x=1.5\)

The walkway is 1.5m wide.

  !