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cal the great plz help

An answer you will be sure to cheat off of? Nah. The explanation is simple. In fact, the answer IS in the link I gave you, you were too lazy to look through it.

Probability:

Number of Yellow Faces

___________________

Total Number of Faces

I am still confused. Could I get an answer?

4N2

A number is divisible by 9 if the sum of the digits is a MULTIPLE of 9.

Solve for N (shouldn't be that hard it's basic adding and dividing)

3 red

2 blue

5 yellow

the probability of drawing either red or blue is

(red marbles + blue marbles)

_______________________

             total marbles

A number is divisible by 6 if it is divisible 3 AND 2.

By divisibility of 3 rule:

2 + 1 + 4 + 2 + 0 + N = 9 + N

Let us try

N = 3 (nope because it is odd so it can't be divisible by 2)

N = 6 (yes!)

N = 9 (nope)

500000  =  A( 1 + .05)^ 10        divide  both sides by  ( 1 + .05)^10

500000/ ( 1 + .05)^10  =  A  ≈  $306956.63

1 - 0.2 - 0.5 = What did you struggle on in this problem?

FV = PV x [ 1 + R]^N

500,000 =PV x 1.05^10

500,000 =PV x 1.62889462677744140625

PV =500,000 / 1.6288946............

PV =$306,956.63

Perfect  squares    =    1, 4, 9 , 16, 25 , 36, 49, 64, 81 ,100

Probability  =  10 / 100   =   1 / 10

AltShaka,

I have looked on his account. He hasn't given free answers, although the answers were boxed and bolded. It depends on the QUESTION ASKER if the answer is "free or not".

If a question asker just looks at the answer and types it in and moves on, then the answer is free. If a question asker learns from the explanation, then the answer was not free.

I am friends with CalculatorUser in real life. I saw your previous posts asking CU and CPhill directly to help, by the looks of it, you seem to be pushing them to answer your question. Would they be giving free answers? They always include at least some explanation and work.

Please take DragonLord's response seriously and improve the quality of your questions next time! You still forgot to include numbers in your question!

Not  familiar  with  this  notation.....however....if it's supposed  to  be

(  n     )        we   have

  n - 2

                 n!

_________________  =

    (n - (n - 2)! (n - 2)!

                    n!

            ___________   =

               2!  ( n - 2)!

                n ( n - 1)

               ________

                        2

123  124  125  126  127  128  129  134  135  136  137  138  139  145  146  147  148  149>>=18 such integers  

Just to clarify

 - Is this supposed to be Combination/Permutation?

 - Or is this something more advanced?

Thanks CPhill!

\(\frac{5*4*3*2*1}{(3*2*1)(2*1)}\)

Can you evaluate this now?

Thank you! CPhill!