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That doesn't work becuase the question asks for "What is the smallest positive integer..." and 0 is not positive.

Hope it helps!

THX, HELPMEEEEEEEEEEEEE   !!!!!

The roots  are    x = 0  and  x = -2

So....we have  this form

y = a (x)( x + 2)       and we can find  a    as  follows

-64  = a (2)( 2+2)

-64  = a ( 2)(4)

-64  = a (8)    divide  both sides  by  8

-8  = a

So....the form is 

y  = -8 (x) ( x + 2)       simplify

y = -8 ( x^2 + 2x)

y = -8x^2  - 16x

Given the x-intercepts, we can set up and equation in the form y=a(x-x1)(x-x2) where x1 and x2 are the x-intercepts. In order to find the equation of the graph, we need to solve for a. Filling out the numbers we get y=a(x-0)(x-(-2)). We then plug in the point (2, -64) as X and Y to get -64=a(2-0)(2+2). That simplifies into a=-8. The equation then turns into -8x^2-16x which is our answer. Graph it to check if it works.

Hope it helps!

use any example: take a 4:2 rectangle- area 8

4 increased by 25%=5

8/5=width

2-8/5=2/5

decreased byy 20%

There is no diagram. Can you attach it?

How about: -7(15) + 5(21) = 0

Let the  value of the  investment  at the start  = A

At the  end of 2006  the value is  1.25A

So....we  need  to  solve  this

(1.25)A  *  x  =  A        divide  both  sides  by  A

1.25 x  =   1            divide  both  sides  by 1.25

x = 1 / 1.25   =    4/5

So  x  = 4/5  =  .80

Then the investment's  value at  the end of 2007  needs to be 80%  of its  value at the  end of 2006

So......it  would need to lose 20%  of its value 

I converted the question to an image, if you can answer this question that'll help a lot! Thanks!

THx so much!!!!

Note  that  the area of the  right  triangle = (1/2)(BC) (AB)

And note  that the  area  between  the right triangle and  the  circle  =  (1/2)pi (AC/2) ^2  -  (1/2) (BC)(AB)  =

(1/2) [ pi  ( AC)^2  / 4  - (BC)(AB)  ]  =    (1/2) [ BC^2 + AB^2 ] / 4  -  (1/2) (BC)(AB)          (2)

The area  of  the two  semi-circles  =  (1/2)  [  (BC/2)^2  +  (AB/2)^2  ]  =  (1/2)  [ BC^2 + AB^2 ]/ 4   (3)

So....the shaded area  =  (3)  - (2)  =

(1/2) [ BC^2 + AB^2   ] /4  -   [ (1/2) (BC^2  + AB^2 ]   / 4    - (1/2) (BC)(AB)  ]  =

(1/2) (BC)(AB)    which  is  the  same  as  the area of  the right triangle

The first question describes a plant cell.

For the second one I'm pretty sure every cell has a vacuole. If it doesn't have a cell wall that means that it isn't a plant cell. Chloroplasts is also found in plant cells. I hope that narrows down some choices for you!

If 14 out of 56 trout caught have been tagged, that means that 1/4 of them have been tagged. Based on that ratio, 1/4 of the total trout have been tagged. So, 144 is 1/4 of the total amount of trout. 144*4=576 trout. 

Hope it helps!

a.   standard  form

(x + 4)  ( x - 8)     expand

x^2  +  4x  -  8x  - 32

x^2   -  4x   - 32

b. vertex  form

complete the  square  on x

x^2  - 4x +  4  -  32  +  4       factor  the  first three terms and simplify

( x - 2)^2   -  28

2x^2  -  5x  +  7  =   0

1.  discriminant  =   (-5)^2  - 4(2)(7)  =  25  -  56  =  -31

2.  Since  the  discriminant  is  <  0,  then  we  have  non-real roots

a.

y =  (x -2)^2  -  9       expand

x^2  - 2x - 2x  +  4  - 9

x^2  - 4x   -  5

 b.   factored  form  :

y  = ( x -5) ( x + 1)

Quadruple  M  is correct!!!!

We have  the form

y = ax^2  + bx  +  c

If  the y intercept is  -6,   then  c   = -6

The x coordinate  of the vertexx is given by  -b/[2a]   = 1  which  implies  that  - b  = 2a  ⇒ b = -2a

And     we  know that

4  = a^(1)^2  - 2a (1)  - 6    simplify

4 = a - 2a  - 6     add 6 to both sides

10  =  -a      ⇒   a   =  -10    and b  (-2)(-10)   = 20

So....the  function  is

y = -10x^2  + 20x  - 6

It would have to go down 20%

It would become 125%. 25/125=.2, which is 20%

I got three

-2(21)+3(15)=-42+45=3