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There are 7 slices per pizza.

There are 49 total slices.

So, there are  49 / 7  =  7 pizzas.

How do you cut it into 7 slices?

Pick's formula for the area is:  A  =  I + B/2 - 1

where  I = number of interior points     =  2

          B = number of boundary points  =  10

A  =  2 + 10/2 - 1  =  2 + 5 - 1  =  6

No it isn't.

It is a negative number.

\(2^{\log_x 7} = 49^{\log_2 x}\\ log_2(2^{\log_x 7}) = log_2(49^{\log_2 x})\\ log_x7=log_2x*log_249\\ \frac{log_27}{log_2x}=2log_2x*log_27\\ \frac{1}{log_2x}=2log_2x\\ \frac{1}{2}=(log_2x)^2\\ (log_2x)^2=\frac{1}{2} \)

What is the surface area of this design?

Hello Guest!

\(A=(4\cdot 5\cdot 4+8\cdot 5\cdot 2+8\cdot 4\cdot 2+4\cdot 4\cdot 2)in^2 \)

\(A=256in^2\)

  !

3x + 44 + (x + 20)  =  180

  3x + 44 + x + 20  =  180

                4x + 64  =  180                                    (simplify)

                        4x  =  116                                    (subtract 64 from both sides)

                          x  =  29                                      (divide by 4)

For:  tan(x + y)tan(x - y)  =  ( sin²x - sin²y ) / ( cos²x - sin²y )

                                       =  [ (sinx + siny)(sinx - siny) ] / [ (cosx + cosy)(cosx - cosy) ]

                                       =  [ (sinx + siny) / (cosx + cosy) ] · [ (sinx - siny) / (cosx - cosy) ]

                                       =  tan(x + y) · tan(x - y)

           5  =  ( x³ - 2x² - 8x ) / ( x + 2 )                                              Note that x can't equal -2.

 5(x + 2)  =  x³ - 2x² - 8x

 5x + 10  =  x³ - 2x² - 8x

           0  =  x³ - 2x² - 13x - 10

           0  =  (x + 2)(x + 1)(x - 5)

Answers:  x = -1     x = 5

xy/(x + y)  =  1   --->   xy  =  x + y   --->   xy - x   =  y   --->   x(y - 1)  =  y   --->   x  =  y/(y - 1)

xz/(x + z)  =  2   --->   x  =  2z/(x - z)

yz/(y + z)  =  3   --->   z  =  3y/(y - 3)

Substituting the third equation into the second:  x  =  [ 2(3y/(y - 3)) ] / [ 3y/(y - 3) - 2 ]

--->   x  =  (6y) / (y + 6)  

Combining this equation and the first equation:  y/(y - 1)  =  (6y)/(y + 6)

--->   y(y + 6)  =  6y(y - 1)

--->    y² + 6y  =  6y² - 6y

--->             0  =  5y² - 12y

--->             0  =  y(5y - 12)

Either  y = 0  or  y  =  12/5                       

If  y = 12/5   --->  x  =  y/(y - 1)   --->   x = 12/7

If  x = 12/7  and  y = 12/5  --->   z  =  3y/(y - 3)   --->   z  =  -12

.09 x   +   .13 (80 000 -x)  = 8000

x = 60 000 @ 9%     20 000 @ 13%

Is it 2?

Plot -5/3 on a number line.

The whole number directly to the left (low side) is the floor of it.

Those symbols are asking for the floor.

Qwerty, please respond with your answer.

Please no one else give the exact answer.   Thanks 

HI, Thank you for the response and explaing your method but I think your answer is incorrect. I am going to giv.e the problem another shot using your techniques. I really appreciate the help!

The common denominator is  (x + 1)(x - 1)

Multiply each term by this and the equation becomes:   A(x + 1) + B(x - 1)  =   x + 2

Multiplying out:                                                                    Ax + A + Bx - B  =  x + 2

Factoring:                                                                         (A + B)x + (A - B)  =  x + 2

Setting the X-terms to each other:        (A + B)x  =  x   --->   A + B  =  1

Setting the constants to each other:                                       A - B  =  2

Solving these two equations:  A  =  1.5   and   B  = - 0.5  

This was posted earlier.....I do not know if anyone has tried to answer it....I do not yet have an idea.

I'm thinking it is something like 2.5   to   92.5 pounds....not sure....

(5 @47.5 + 2.5)/6 = 40                     (5 at 47.5+ 92.5)/6 = 55

Since it is shifted to the right 3 units, each x-term should be replace with"x - 3".

New equation:  y = (x - 3)³ - 2(x - 3)

Its wrong

pls halp

Since the two bases are regular hexagons, they can be divided into 6 equilateral triangles.

If the height of an equilateral triangle is 3·sqrt(3), its base is 6 and its area = ½·6·3·sqrt(3) = 9·sqrt(3).

Therefore the area of the regular hexagon = 6·9·sqrt(3)  =  54·sqrt(3).

Doubling this to get the area of both bases = 108·sqrt(3).

Each side is a rectangle whose area is 6·8  =  48.

For all 6 sides:  6·48  =  288.

Total surface area  =  108·sqrt(3) + 288.

Last term=3 + 11*(20 - 1)
                =3 + (11*19)
                =3 + 209
                =212
Sum =[F + L] / 2 * N, where F=First term, L=Last term, N = Number of terms.
Sum =[3 + 212] / 2 * 20
         =215 / 2 * 20
         =107.50 * 20
         =2,150

Since DBE and CBA are straight lines, angle(DBA) = angle(CBE) because they are vertical angles.

Somce there are 180^o in every triangle:

     angle(D) + angle(A) + angle(DBA)  =  180^o  =  angle(C) + angle(E) + angle(CBE)

            angle(D) + angle(A) + angle(DBA)  =  angle(C) + angle(E) + angle(CBE)

                              angle(A)                         =                    angle(E)         (by sutbraction)

Do you mean to have the number 25 repeated?

I think that you mean a combination, that is evaluated as:  8! / ( 3! · 5! )  =  56

Write each log as a common log:

   log₂(x)   =  log(x) / log(2)

   log₃​(x)   =  log(x) / log(3)

   log₄(x)   =  log(x) / log(4)

   log₅(x)   =  log(x) / log(5)

On the left-hand side, we will end with:  [ log(x) ]⁴  /  [ log(2) · log(3) · log(4) · log(5) ]

On the right-hand side, we will need to multiply each term by an appropriate term to get the common denominator

of [ log(2) · log(3) · log(4) · log(5) ].

Multiply the first term by  log(5) / log(5)

        the second term by  log(4) / log(4)

            the third term by  log(3) / log(3)

          the fourth term by  log(2) / log(2)

Adding those terms together, you will end with the numerator of  [ log(x) ]³ · [ log(2) + log(3) + log(4) + log(5) ]

Setting the two numerators together:  [ log(x) ]⁴  =  [ log(x) ]³ · [ log(2) + log(3) + log(4) + log(5) ]

Dividing out  [ log(x) ]³ , we get  log(x)  =  log(2) + log(3) + log(4) + log(5)

                                                   log(x)  =  log(120)

                                                         x   =   120