All Answers 355923 Answers

\(\left |ax+b \right |=c\)

Modulus equation (The absolute value) 

This can be either: 

\(ax+b=c\)

\(ax+b=-c\)

Solve for a in both cases. 

\(a=\frac{c-b}{x}\)

\(a=\frac{-c-b}{x}\)

Error. Answer below..

а) 2,5 + 0,42 =

Hallo Gast!

\( 2,5 + 0,42 = 2,92 \)

  !

 9^5

(6x+34)+(11x+10)=180

(6x+34)=z

17x+44=180

17x=136

x=8

6(8)+34=82 

z=82

q=quarters

n=nickles

q+n=13

.25q+.05n=2.45 (multiply by 100)

25q+5n=245

n=-q+13

25q+5(-q+13)=245 (Substition)

25q-5q+65=245

20q+65=245 (Substract 65 from both sides)

20q=180

q=9 

9+n=13

n=4

To check

.25(9)+.05(4)=2.45

Thank you so much, I have been stuck on this question all day

The number of macaroons you need total is 36. This is found by multiplying 9 and 4, which is 36. 36-17=19 (You need to make 19 more macaroons).

\({x +17 \over 9}=4\)

\(x+17=36\) Subtract 17 from both sides
 

\(x = 19\)

Triangle at the close end                             (1/2) • 6 • 8    =   24 

Triangle at the far end                                 (1/2) • 6 • 8    =   24 

The end opposite the point                                    6 • 12  =   72 

The side you can see                                             8 • 12  =   96 

The side you can't see                                         10 • 12  =  120

Add them up                                                                           336 square feet 

There are 5 real roots.

1. Angle x = 65 degrees.

2. The ratio is (2/3)^2 + (2/3)^3 = 20/27.

3.

Because of the spherical coordinates, phi = c traces a cylinder.  So the answer is (E) cylinder.

The smallest number of integers in the domain of f is 22.

For example: 123 is the smallest 3 digit integer with digits strictly increasing left to right.

We list smallest numbers like cases in the example:

1 (does not count)

12

123

1234

12345

123456

1234567

12345678

123456789

Notice how for each of these cases. The number with \(n\) digits has \(10-n\) cases that fit the problem. Starting with the two digit numbers, the number of cases that fit the problem is 8 + 7 + 6 + 5 + 4 + 3 + 2 + 1 = \(\boxed{36}\)

I'm not sure if this is correct, but it is my attempt on the problem.

Upload it correctly. 

Please edit your question so that it reads properly.

Nice!  I like that strategy!

Sorry its \(0\) to \(9\)!

Oh yaaa youre right AnExtremelyLongName.

You missed some latex!

I think it's 5-digit

The largest digit possible is 123456789. There is a limit.

Which integers? 2-digit, 3-digit, 4-digit......etc????

5 step solution

1. Divide AOB in half and use right triangle trigonmetry to find the base and height. (Alternative method, you can use law of cosines to find AB then proceed with Heron's formula)

2. Knowing the base and height, you can find the area of triangle AOB.

3. Find the area of the major portion of the circle that contains major arc AB

4. Add the area of the major portion and triangle together. Subtract that from the total circle area.

5. Your result is your answer.

Point-slope point:  y - y₁  =  m(x - x₁)

m  =  -1/2                                                        y - -6  =  -½(x - -4)

(x₁, y₁)  =  (-4, -6)                                            y + 6  =  -½(x + 4)

                                                                        y + 6  =  -½x - 2

                                                                             y  =  -½x - 8