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Infinity is not a number, so trying to use the arithmetical operators (addition, division, multiplication, and subtraction) on it is invalid. 

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I completely understand, TacoBell.  I can't count the number of times I've started working a problem that had no answers, and by the time I post my answer, I find someone had got in and posted their answer while I was still working.  Sometimes it makes me feel like throwing my hands up and saying, "What's the use!"  Frustrating, but, even if somebody else has answered, you should go ahead.  You might have a different slant on it, and sometimes it's that slightly different viewpoint that's just the thing that will light the bulb over the questioner's head.  The bottom line here is helping others. 

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no its okay , thank you so much for yuor help. gonna look over it right now and see if  i have any questions

1, 2, 5, 5, 5, 5, 8 =7!/4!      =210 permutations
2, 2, 4, 5, 5, 5, 5 =7!/4!.2! =105 permutations
1, 4, 4, 5, 5, 5, 5 =7!/4!.2! =105 permutations
                             TOTAL= 420 - codes possible

Sorry this took so long... I was missing a step and it took me FOREVER to find out what it was. 

1. \(\frac{sin\:x}{1-cos\:x}=csc\:x+cot\:x\)

2. \(\frac{sin\:x}{1-cos\:x}=\frac{1}{sin\:x}+\frac{cos\:x}{sin\:x}\)

3. \(\frac{sin\:x}{1-cos\:x}=\frac{1+cos\:x}{sin\:x}\)

4. \(\frac{sin\:x}{1-cos\:x}=\frac{sin\:x(1+cos\:x)}{sin^2\:x}\)

5. \(\frac{sin\:x}{1-cos\:x}=\frac{sin\:x(1+cos\:x)}{1-cos^2\:x}\)

6. \(\frac{sin\:x}{1-cos\:x}=\frac{sin\:x(1+cos\:x)}{(1-cos\:x)(1+cos\:x)}\)

7. \(\frac{sin\:x}{1-cos\:x}=\frac{sin\:x}{1-cos\:x}\)

plz hep to put in pi

dont know how to do that

1. circumference of a circle: 2r*pi=12pi

2 circumference of a circle also =dr=14pi

YOU MUST PUT YOUR ANSWERS IN THERMS OF PI

1936

Similar to you previous post

tan 42 = opp/adj = height / 400

tan 42 = height / 400       solve for height

Tan (angle elev) = opp/adj

                          = 12 / 15

arctan (12/15) = angle elev=.........

According to the tax table above 

.4 (45600 - 43000)  + .2 (43000 - 11 000) = ............   tax

a=1;b=1;c=1;d=1;e=1;f=1;g=1;p=0; cycle:n=a*1000000+b*100000+c*10000+d*1000+e*100+f*10+g; if(a*b*c*d*e*f*g==10000, goto loop, goto next);loop:printn," ",;p=p+1; next:g++;if(g<10, goto cycle, 0);g=0;f++;if(f<10, goto cycle, 0);g=0;f=0;e++;if(e<10, goto cycle,0);g=0;f=0;e=0;d++;if(d<10, goto cycle,0);g=0;f=0;e=0;d=0;c++;if(c<10, goto cycle,0);g=0;f=0;e=0;d=0;c=0;b++;if(b<10, goto cycle,0);g=0;f=0;e=0;d=0;c=0;b=0;a++;if(a<10, goto cycle,0);print"Total = ",p

OUTPUT = 420 such codes

plz can you show me for the second one step by step plz

1.f=6 g=8

2.65%

Area A =      6 x (10+18)/2  ft²

Are B = Area C = 4 x 12  ft²

^{You should be able to take it from here !}  

Second one, 

Draw a line from B to D 

Notice it is two right-angled triangles.

area of triangle \(\frac{1}{2}*b*h\) (b=base, h=height)

so

Area of the first triangle: \(\frac{1}{2}*18*7.5=67.5cm^2\)

Area of the second triangle: \(\frac{1}{2}*15.6*11.7=91.26cm^2\)

Thus area of the quadrilateral is the sum of both

\(67.5+91.26=158.76cm^2\)

The circle 2x^2 = -2y^2 + 12x - 4y + 20 is inscribed inside a square which has a pair of sides parallel to the x-axis. What is the area of the square?

First one,

"The perimeter of the triangle is 30" 

Perimeter is the sum of outer lines of a shape. 

(The three sides of this triangle)

so, 3a=30 thus a=10 cm

Rectangle's perimeter = 2(l+w)=2l+2w , given l=a and w=b then

2a+2b=30 

Since a=10 

20+2b=30 , 2b=10 , b=5

Area of square is side squared.

b is the side so \(b^2=5^2=25\) \(cm^2\)

Side of the square is 10 cm   area = 10 x 10 = 100 cm²

^{Upper left triangle area = 1/2 bh = 1/2  3 x 10 = 15 cm^2}

^{Lower right triangle area = 1/2 6 x 10 = 30 cm^2}

^{Total UNshaded area = 45 cm^2}

^{Then shaded area = 100 -45 = 55 cm^2    out of 100 cm^2    =   55 %}