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Are you sure???

I like the day care, it was so funny!

oh okay!

There is a very small chance but likely not because you will be provided with an escape pod that will automatically know where to go.

No. (This is a reality show.)

We are friends. But Melody is close to the answer, btw.

LOL!

i think DragonSlayer is too pleased with CPhill as he is always struggling to make him rich!DS we are CPhill's friends so make us rich as well!

Are we going to die on the trip?!?!?!?!

No, Melody. You are wrong. Hahaha! No one will solve it! CPhill, you kept your money.

Why is it a bit thank you?

19 + 2[6-(6-4)2]

19 + 2[6 - 2*2] <--Parentheses first

19 + 2[6 - 4] <--- Multiply next in brackets

19 + 2[2]

19 + 4

23.

4(r - 20) + 3r

4(15 - 20) + 3(15)

4(-5) + 15

-20 + 15

-5.

Note that this a difference of squares:

where a = q and b = 1 (a^2 - b^2)

Therefore, our answer is q^2 - 1.

Por cada 1 a 3 puntos, como se cual usar? 

Si 1 punto adicional --> 113 - 46 = 67 --> 67*100 = $6700 + $4200 = $10,900.

Si 2 puntos adicionales --> 113 - 46 = 67 --> 67/2 = 33.5 --> 33.5*100 = $3350 + $4200 = ....

Si 3 puntos adicionales --> 113 - 46 = 67 --> 67/3 = ........................

?

Necesitas usar el "2nd" key primero en la calculadora. Entonces, usas el "atan" key. 

Tambien, puedes escribir atan(#) cuando # es un numero o otra cosa.

Are you trying to apply this to a function such as f(x) = x^2 + 1?

If we plug in x = 1 and x = -1, we obtain a value of 2 (two different inputs yielding the same output).

5.5 --> Note that if you multiply by 10, you get 55. To get back 5.5, you have to divide by 10. 

So, 5.5 --> 55/10.

You can simplify this by dividing both the numerator and denominator by 5:

55/10 --> 11/2.

-2.6*-5.5 =

14.3

I assume this might be.....(4/5)*(10x+4)-8x+(5/2)...if so, we have

8x + (16/5) - 8x + (5/2) =

(16/5) + (5/2)  =

[16(2) + 5(5)] / 10 =

[32 + 25] / 10 =

57 / 10  =

5 + 7/10

|6 + z | - |-7|  =

l6 + z l - 7

Notice, that if z ≥ -6, then the answer is

6 + z - 7    =

z - 1

But, if z < -6, then the answer is

- z - 13

So we have .7777.......

= 7/9

Let x be the original cost of one computer and y be the original cost of one printer.

So, the first equation is

3x + 1y = 1800

And when the price of a computer fell by  $500 we have....

2(x-500) + 2y = 1300     → 2x - 1000 + 2y = 1300→ 2x + 2y = 2300

So we have 2 equations

3x + 1y = 1800

2x + 2y = 2300

Multiplying the first equation by -2 on both sides, we have

-6x - 2y = -3600

2x + 2y =   2300

And adding them together, we have

-4x = -1300

Then the original cost of the computer was $325

And Melody's answer is correct !!! [This problem probably needs some "tweaking" so that the answer is  a "real-life" quantity...!!!]

(A*b*c)^4*3/(b*c)^3*b^3/27a^5    So we have, taking it in steps.......

[A⁴b⁴c⁴]*[3] /[b³c³] = 3[A⁴bc]

3[A⁴bc]*[b³] = 3[A⁴b⁴c]

3[A⁴b⁴c] / [27a⁵ ] =

[A⁴b⁴c] / [9a⁵ ]

(5 + 5677643628300219/10,000,000,000,000,000) i

$${\mathtt{9.09}}{\mathtt{\,\times\,}}{{\mathtt{10}}}^{{\mathtt{8}}}{\mathtt{\,-\,}}{\mathtt{2\,569.98}} = {\mathtt{908\,997\,430.02}}$$

Very impressive, guys....!!!!