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Same here. It says "blocked by moderator"

It still is not showing up for me...I can see it in the answers tab though.

Mmmmm....I can see it just fine....not showing up for you  ????

Yep....that's all you could do    

f(x)  = 4sinθ  is actually a sine curve with an amplitude of 4.....not what we want in this case.....

Your image is "blocked by moderator."

Thx, LuckyDucky   !!!!!

Nope..for instance...see here  :

The median =[969 + 970] / 2 =969.50

See - "https://web2.0calc.com/questions/help-plz_70717"

I didn't see r = 4 sin theta as an option for the drag and drop so I just put in f (x) = 4 sin x

(x -2)^2  + (y - 7)^2  =  13

The center  = ( 2, 7)

y =  (-3/2)(x + 1) + 5

This would  mean the the point  ( -1, 5)  is  on the circle  (which is true)  because  (-1-2)^2  + (5-7)^2  =

3^2 + 2^2   =   13

It  also means that the slope  of the  line  containing the center  and this point is

[ 7-5] / [ 2 - -1]  =  2/3

The  tangent line line at (-1.5)  would have  a slope of -3/2

Looks like Leslie is correct  !!!

See the graph here  : https://www.desmos.com/calculator/6cvmd0qkqr

Looks good.....nice job  !!!!

One small correction to the answers.....

We should  be graphing

r  = 4 sin θ

 y = mx + b

y = -3/7 x + 18         x intercept is when y = 0 .....put that in

'0'  = -3/7x + 18        solve for x

Volume of a sphere =   4/3 pi r^3        If 9 = r   then just plug in and compute

                                                                if 9 = d     then  r= 9/2     plug in and compute

                                                                     answer will be in cm³ units

The  circles will be tangent  at the  center of the rectangle  = (50, 25)

Dropping a perpendicular  from  this point  to the  bottom side of  the rectangle  will form one leg of a right triangle  = 25

Connecting the center  of the bottom semi-circle to the  center of the  square  is the  hypotenuse of this right triangle   = R

And the other leg of thisright triangle =  50  - R

So we have

(50-R)^2  + 25^2  = R^2      simplify

R^2  - 100R  + 2500 + 625  = R^2

100R  = 3125

R  = 3125/100   =  125  /  4  = 31.25 

We can form a 5-12-13  right triangle  by connecting the centers  of the  circles  and  then drawing a parallel line to the base of the figure  intersecting the two  vertical  lines in the figure....the length of this line = 12

And we  can  create  two more  right triangles

One on the left with  legs of  (9-r) , x   and a hypotenuse of (9 + r)

And one  ont the right with legs of (4 - r) (12-x)  and (4 + r)

And we have  this system of equations

(4 - r)^2 + (12-x)^2  = (4 + r)^2        

(9 - r)^2  + (x)^2  = (9 + r)^2

These are a little sticky to solve  but using WolframAlpha  we  find the  solutions for   x  and r  to be

x  = 36/5  and  r   = 36/25  = radius of the smaller circle

So....the  equation of the  small circle  is   ( x - 36/5)^2  + ( y -36/25)  = (36/25)^2

Here's a pic : https://www.desmos.com/calculator/5yzqb20sxi

Go to this page and see lots of details on the reaction:

https://www.wolframalpha.com/input/?i=Convert+from+moles+to+grams+++Pb%28NO3%292+%2B+KI+%E2%86%92+PbI2+%2B+KNO3

Are you just trying to balance the equation?

Pb(NO3)2 + KI → PbI2  KNO3       Need two I atoms   so add 2 to the left side  

Pb( NO3)2 + 2  KI → PbI2  KNO3       Now we need to balance the right side since we added 2 KI add 2 K to Right side 

Pb(NO3)2 +  2 KI → PbI2   2 KNO3        Now it is 'balanced'    One Pb on both sides, two K's , two NO3's , two I's

Geat explanation!

I fixed the question.

That's not true at all this is my own.

"It" being the answer "x = sqrt(10) - 2, -sqrt(10) - 2."

Yeah, sorry.