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Yeah, snow. 
 

Rain is water and has surface tension so is not "not together" but snow is technically seperate but gathers on the ground into one.

The area of  this right triangle =  (1/2)(product of the legs)  = (1/2) (20)(13)  =  130 ft^2

So.....using this

Area  also equals  (1/2) base * height

130  = (1/2) (23.9) (height)      multiply both sides by 2   and divide both sides by 23.9

260 / 23.9 =  height ≈  10.9 ft

I have answered this question last month or so.

See if you can find the question in my answers.

THX, Dragan  !!!!

If you walk  at  3 mph   then  the normal time to  make it to school  is

(distance)  / (rate)  =    1 mi  / (3mi / h)  =  (1/3) hr  =  20 min

If you  walked  the first  half mile at 2 mph   the  time it took you  is

(1/2)mi  /( 2 mi / h)  =  (1/4) hr  =  15 min

Then....you must walk the last  1/2 mile  in 5 min  =  1/12  hr

So....to find the rate that you must run we have

distance / time  = rate

(1/2) mi  / (1/12) hr  = (12/2) mi / hr   =   6 mi / hr   =  6mph

See the following  image

Let the side of the hexagon  =  S

Then the  area  of the hexagon  =  6(1/2)S^2 sqrt (3) / 2   =   3sqrt(3)S^2 / 2  =  (3/2) sqrt (3)S^2

Note that  the  area  of  triangle  ABP  =

(1/2)(AB)(BP) sin ABP  =

(1/2)(S)(1/2)S * sin (120)  =

(1/2) (S) (1/2)S * sqrt (3) / 2 =

(1/8)sqrt (3) S^2

Using symmetry  we  have  three other triangles  congruent to triangle  ABP

So....the total area  of these  4  triangles =  (1/2)sqrt(3) S^2 

So...the area of  APDQ =  (3/2 - 1/2)sqrt(3)S^2  = sqrt (3)S^2

So.....the  ratio of the area of APDQ  to  the area of the hexagon  =

 sqrt (3)S^2                  2

_____________   =   ___   

(3/2) sqrt (3) S^2         3

Excellent job, Phill !!!

Answer is E, because you have to: b + b then its e. Quick Math!

Second one

Using the same idea as in the first one

The top rectangle  has dimensions  10 x (27 - 9)  =  10 x 18   = 180 cm^2

The bottom rectangle  has dimensions  9 x 24  =  216 cm^2

Add these together to get the total area

There are 9 numbers that satisfy all the conditions in your question:

19 , 29 , 39 , 49 , 59 , 69 , 79 , 89 , 99 , Total =  9

(1, -3) = (x , y)

csc θ =  r / y

r = sqrt  (x^2 + y^2)  =  sqrt ( 1^2 + (-3)^2)   =  sqrt (10)

So

csc θ  = sqrt (10)  / - 3  =   -sqrt (10) / 3

The radius  = 5 in

The area of the  cheesecake  =     pi * (5)^2  =  25 pi

So....the  area  divided by the number of  slices  will  equal the area  of one of the slices.....let  the number of slices  = N

So  we  have this

(25 pi) / 12  =  25 pi  /  N         divide out pi

(25/12)  = 25 / N          rearrange as

N =  25  / ( 25/12)

N = (25/1) ( (12/25)

N  = 12

The numerator  can be written as the sum

(n) (n + 1)  / 2        so we have

(n)(n + 1)

________  =   10      simplify

2 * 2n

n + 1

_____      =    10       multiply both sides by  4

  4

n + 1  =  40

n = 39

x^4 - 27x^2 + 121    

Let us guess  that  the factorization may be

(x^2 + ax + 11)  (x^2 - ax + 11)        expand

x^4 - ax^3 + 11x^2  + ax^3 - a^2x^2 + 11ax  + 11x^2  - 11ax + 121   simplify

x^4  + 22x^2 - a^2x^2 + 121

Note  that, equating coefficients,    (22 - a^2) =  -27     rearrange

22 + 27  =  a^2

49 = a^2

Take both roots

7 = a    and  -7   = a

So we have

( x^2  + 7x  + 11 )  (x^2 - 7x + 11)

The sum is

2x^2  + 22

The answer is either rain, or snow.