All Answers 355936 Answers

See my answer   under  your original question, GM

To  find AOB, as geno points  out, we  need to  take the arctan  (tangent inverse)  to  find  this angle we have

arctan ( 5/4)  ≈  51.3°

Since AC  is  tangent  to circle P   at C  and  PC  is a radius.....there form a right angle

So  angle PCB  =  90°

pi/6   is   30^o

pi/6 R x 180^o/(pi R) = 30 degrees    sin 30 degrees  = sin pi/6 = 1/2

Two circles with the same radius overlap each other. Their circumferences cross each other's center. How much of the area of either circle in percentage is the overlapped area? Give your answer in the nearest tenths.

y = x^2  - 2    ⇒   x^2   =  y + 2    (1)

x^2  + 4y^2  =  16     (2)

Sub (1)  into (2)    ans we have that

( y + 2)   + 4Y2      =  16

4y^2 +  y  -  14   =   0

(4y - 7) ( y + 2)  =  0

Set  each  factor to  0   and solve  for  y   and we get that

y = 7/4       and    y  =  -2

And  y = x^2  - 2  ....so...

7/4  = x^2 - 2                        -2  = x^2    - 2

15/4  = x^2                             0  =   x^2

                 Take  both roots

x = sqrt (15)/2        x = - sqrt (15)/2   and  x    = 0

So.....we have three points  of intersection

Seethe graph here  :  https://www.desmos.com/calculator/tgmads5grb

181 градус 02 минуты - 31 градус 08 минуты, как это написать в калькуляторе ?

181 Grad 02 Minuten - 31 Grad 08 Minuten, wie schreibt man das in einen Taschenrechner?

Привет, товарищ!

\(181°2'-31° 8'=149°54'\)

наилучшие пожелания

осел 

  !

Let's solve for a.

3a+4b=a−8b+24

Step 1: Add -a to both sides.

3a+4b+−a=a−8b+24+−a

2a+4b=−8b+24

Step 2: Add -4b to both sides.

2a+4b+−4b=−8b+24+−4b

2a=−12b+24

Step 3: Divide both sides by 2.

2a

2

=

−12b+24

2

a=−6b+12  <------final answer

Thank you!!

Ok if you are going to post a question from your homework fine but if you want to cheat on all of them no.

Don't cheat on your AoPS.

AoPS problems are copyrighted under United States Law and you are technically violating it.

the measure of angle EGF = 

EGF  is  an insribed angle  which  intercepts  minor arc EF

Thus....it measues  (1/2)  of  this arc   =  40°

the measure of angle GED 

Note  that  angle DFG  = 80°

So.... minor arc  DG   = 160°

And angle GED intercepts the same arc

So its  measure also  = 80°

the measure of minor arc DG =    160°

the measure of angle FDE =  (1/2)  minor arc FE  = (1/2) (80)  =  40°

Since AB and EF are parallel.....drop a perpendicular  from AB to EF

Then  both of the angles formed by this perpendicular  = 90°

And angle ECD is supplemental to angle  BCE....so angle BCE  = 180 - 55   = 125°

And we  have  an irregular pentagon......and the sum of the interior  angless =540°

So  angle CEF  can be found as

CEF  +  90  +  90  +  125  + 120    = 540

CEF  + 425  = 540

CEF  = 540  - 425  =  115°

First, I'll just disregard the fact that this is an AoPS question.

 BCD is a straight line, so we have BCE = 180 . We draw a line CG, which is parallel to AB and EF.

AB || CG, so

\(\angle ECG = \angle BCE - \angle BCG = 125^\circ - 60^\circ = 65^\circ\)

CG and EG are parallel so

\(\angle CEF = 180^\circ - \angle ECG = \boxed{115^\circ}.\)

ECB = 180 - 55 = 125

Draw a line from F to A   so you have two right angles in a pentagon

Interior angles of a pentagon =  (n-2) 180 = 540

then   CEF = 540 - 90 -90 -120 - 125 = 115 ^o

87  =  44 + 43  (but 43 is prime)

87  =  45 + 42  (both are composite) and their difference is?

a = - .6     b= 2.4     c = 5.5 

use Qudratic Formula:

\(x = {-b \pm \sqrt{b^2-4ac} \over 2a}\)           x= 5.269    and     ............

x *.7 *.8 = .56x    

so price is  56 % of original price.....   or 44 % off

a)   32 = .005 x^2 - 2x + 200        solve for  'x'

b)   18 = .005 x^2 - 2x + 200        solve for 'x'

c)     average  =   (assuming you got correct a and b parts) =  (140 - 120)/ (4.23 seconds - 4.0 seconds) = ......... f/s

Stop trying to cheat on AoPS homework.

14 out of 18 are   not blue       14/18 = 7/9

Well, it two sides of a triangle are 7 and 10, the third side must be more than 3  (10 - 7)

and, at the same time, must be less than 17 (7 + 10)

So, you are looking for values of x such that:  3 < x² < 17.

You'll need to list all the values of x that solve that inequality.