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The pitch ( which is a playing field)    that is 3 meters wide

     the roller is 1.5 meters wide....so you would have to roll up one side and down the other to completely cover it   :  2 passes

     the circumference of the roller  is pi d  = pi (.6 ) m = 1.885 m per revolution

     to go 20 meters you would have to go   20 m / 1.885 m/rev   = 10.61 revs  

             but remember....you have to make TWO passes      10.61 rev per pass x 2 passes = 21.22 revolutons

Ahhhh you're right, for some reason I was thinking squared when I wrote the answer haha.

Thought I was pretty clear....what part do you not understand..

(Please do not repost questions.....respond to original thread when you need further help....)   

Isnt cubic meters represented as   m^3? You're right but it would be C I believe

Kilogram per cubic meter. That's density. So the answer would be B.

My guess is water  .....

Surface area includes the two ends   2   *  pi r^2 = 2  pi (.3)²  m²

   plus the lateral area     pi * d * width  =   pi (.6)(1.5)  m²

3 meters wide would mean yo would have to make    3 m / 1.5 m = 2 passes to cover the pitch

20 m long  divided by the circumference ( pi (.6))       x   2 passes  = .........   revs

V^(1/3)   means   \(\sqrt[3]{V}\)

\( \sqrt[3]{243}\) = cubrt ( 9 * 27) =  3 \(\sqrt[3]{9}\)

Then I probably won't know how to answer it.

discrimnant of the Quadratic Equation must be positive

\(x = {-b \pm \sqrt{b^2-4ac} \over 2a}\)   

b²-4ac   is the discriminant        (-4k)^2 - 4 (1)(k) >0

                                                     16 k^2 - 4k > 0

                                                       4k (4k-1) > 0

                                                         k = 0   or 1/4

Thanks for the question. the diameters of the spheres are 12 cm so the height of the cylinder is 48 and the volume of the cylinder is 36*48pi/3=1728pi. then we find the volume of the spheres*4. The volume is 288pi 1728-4*288=576pi is the answer.

The part that changes the period from 2 pi is this:

3π/4

2pi / (3pi/4) = 8/3 = period

Both of those are wrong

I'm not sure, that's all the question states

1. By the cosine law, cos B = 4/13.

2. By the sine law, BD = sqrt(3)/3.

this is the question 

Can you restate the question so I can answer it?

1. 294/6=49 and sqrt(49)=7 so the side length is 7 and the volume is 343cm^3

2. Ellie can put in 6 boxes as a height, 8 boxes as a length, and 4 boxes as a width so 6*8*4=192 and 192/3=64 so it will take her 64 minutes.

Where is the variable x?

the area of the triangular base must be 5, as 35/7=5 and 4x/2 where x is the height must be equal to 5. 2x=5 so x=2.5, which is the height.

If all have the same degree and if real numbers a,b, and c are the coefficients and c does not equal a and b or any other inequality, then one of the numbers will always exceed the others.

how do i prove that?

Lol this moderation(not an answer)