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60 inches. 49+52+53+55+58+58+59+60+61+61+62+66+68+69+69=900 and there are 15 players so 900/15=60 is the answer.

please hrurry night shade

61 sorry

What is the median?

Welcome!!!

There  is  another way to solve this

The product of the roots =   k/2

       13   - √131                                                13    +  √131

If    _________    is     a root  then  so  is      ____________

           4                                                                 4

So   ( 13 - √131) / 4    *  ( 13 + √131)  / 4   =       (169  - 131) / 4  =  38  / 16

So

38/16  =   k/ 2           mutiply through by  2

2 * 38 / 16 =   k

76/16  =  k    

19/4   =  k

b is about 16.8, angle a is about 23.3 degrees, and angle b is about  123.7 degrees.

In a certain pentagon, the interior angles are  a b c d and e. where a b c d e are integers strictly less than 180. ("Strictly less than 180" means they are "less than and not equal to" 180.)

If the median of the interior angles is  and there is only one mode, then what are the degree measures of all five angles?

Can you post the question itself because the numbers are missing?

I understand now, thanks so much for the help!

It  must  be that   the discriminant   (b^2 - 4ak)  =  131

So

(-13)^2   -  4(2)(k)  =  131             simplify

169  - 8k  =   131        rearrange as

169 - 131   =  8k

38  =  8k       divide both sides by   8

38/8   =  19/4   =   k

geyser?

Let AB  =  BC  =   x

The semi-perimeter  =    ( 2x  + 20)  /  2    =  x + 10     =   s

Using Heron's

Area^2  =  s  ( s - x) ( s - x) ( s -  20)

240^2  = (x + 10) ( 10) ( 10) (x - 10)

240^2  =  100 ( x^2  - 100)

240^2 /100  =  x^2 - 100

576  =  x^2  - 100

676  =  x^2        take the positive root

26   =   x

The perimeter  =   2x + 20   =    2(26) + 20   =   52 +  20   =   72

tan x  +  cot x   

___________  =

csc x cos x

(sin x / cos x)  + (cos x / sin x)

_________________________   =

   (1/sin x) * cos x

sin x / cos x                   cos x / sin x

____________   +       ___________    =

 cos x  / sin x                 cos x / sin x

(sin x / cos x) ( sin x / cosx)    +     1    =

sin^2 x

_________     +      1        =

cos^2 x

tan^2 x   +   1   =

sec^2 x

oh dude, i got the answer! 

i dont know but i just realized thats an absolute value or did u mean brackets?

    n!                         (n) ( n - 1)

_________   =       __________  =   (1/2) ( n )  ( n - 1)   =  (1/2) (n^2 - n)

(n - 2)! 2!                      2

So.....I guess you  want to set this  to  0 ???

(1/2) ( n^2  -  n)  =   0        multiply  both sides  by 2

n^2 - n    =   0

Sea? 

first of all, i also dont understand who heron is.
but idc about heron, I can solve it without heron
..
look dude, we are gonna get the perimeter by this:
sorry i did not have any geometrical materials, hope u dont think its a slice of pizza!

guys, this took me ages, so give me a like, heart and remember to turn on notification to get the latest answer! 

Maybe  a comet?

Maximum height will occur at TIME   t = - b/2a           a = -16   b = 28

this is the TIME of maximum height    .....substitute tis value of time into the equation for 't' to calculate the maximum HEIGHT

Colours? 

V_cone  =   (1/3) pi r^2 *  h

So.....we have

200  = (1/3)pi r^2  * h       multiply  both sides by 3

600 =pi r^2  *  h          solve for  h

600 /[ pi r^2 ] =  h  =  height of pyramid and cone

The  volume  of  the  pyramid  =  (1/3)  side ^2 * h

The  base  of the pyramid  will  be a square inscribed on  the crcular base  of the cone

The  radius of the cone  = r    and the diameter  =  2r

So.....the side  of the  pyramid  =  2r/√2  =  √2 * r

So.......the  volume  of  the  pyramid  =

(1/3) ( side)^2  * height

(1/3) (√2 * r)^2  *   ( 600 /[pi r^2] )  =

(1/3) ( 2r^2) * 600  /[ pi r^2 ] =

(1/3)  (2  * 600)  / pi   =

400/ pi in^3   ≈  127.3 in^3

Also the TOTAL area of the cylindrical roller is this:

Surface area includes the two ends   2   *  pi r^2 = 2  pi (.3)2  m2

   plus the lateral area     pi * d * width  =   pi (.6)(1.5)  m2 

The RED part is the curved surface area your question asks for......