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You subtract the radians that are inside the parentheses and you place that answer within the parentheses of

the answer..

Specifically:  a·cis( 7pi/6)  /  b·cis( pi/4)  =  c·cis( 11pi/12 )

You are given the value of a:  12sqrt(2)  and the value of b:  3sqrt(3).

You need to find the value of c by dividing the value of a by the value of b 

and you place this answer in front of the  "cis( )"  part  --  which is the empty box before (and, in this case, on the

line above "cis(    )"

Right scalene Pythagorean triangle
Use Heron's formula and the Law of Cosines to find the angles and the areas. Or, use Pythagoras's Theorem to do the same thing.

Sides: a = 3 b = 4 c = 5

Area: T = 6
Perimeter: p = 12
Semiperimeter: s = 6

Angle ∠ A = α = 36.87° = 36°52'12″ = 0.644 rad
Angle ∠ B = β = 53.13° = 53°7'48″ = 0.927 rad
Angle ∠ C = γ = 90° = 1.571 rad

Height: ha = 4
Height: hb = 3
Height: hc = 2.4

Median: ma = 4.272
Median: mb = 3.606
Median: mc = 2.5

Inradius: r = 1
Circumradius: R = 2.5
Area of the Incircle =1^2pi
Area Circumcircle   =2.5^2pi
Ratio of the areas =1:6.25

2000 = 2^4 * 5^3 =25,558 - the smallest integer.

Look up. Pythagorean triples......   I think you will find there are none that are all odd # 's.......interesting.....

thanks so much!

Thank you so so much! You've helped me a lot omg

 4.5 hr x 12m/hr = 54 miles

x = 54*cos(143) = -43.1 m

y = 54 *sin(143) = 32.5 m

43.1 m. South.      32.5 m east

I'm just going to straight up tell you the formula ffor trial and error. I don't know any smarter way because I'm not smart. :P a/180+2=n. N is how many sides, and a is the amount of angles. I got this from  a=(n-2)/180. So you do... 360 also 120*3. (360+150*n)/180+2. Solve this multiple times until you get a whole number. BTW... It's 9 sides. (360+150*6)/180+2=9. 

I'm just going to straight up tell you the formula ffor trial and error. I don't know any smarter way because I'm not smart. :P a/180+2=n. N is how many sides, and a is the amount of angles. I got this from  a=(n-2)/180. So you do... 360 also 120*3. (360+150*n)/180+2. Solve this multiple times until you get a whole number. BTW... It's 9 sides. (360+150*6)/180+2=9. 

You already posted this.      And I already showed you how to solve it.....

10000 (1 + .06)⁵ = ........

Thank you Guest! The answer was 15.

x+7 <5    yields    x < -2

x+7>-5   yields     x > -12

x+7>2   yields   x > -5

x+7 <-2 yields   x < -9

combining     ( -12,-9) U ( -5,-2)

a +n  = 4 (b-n)       a = 4b - 5n     and

a-n = 3 (b+n)         a = 3b + 4n        multiply THIS equation by 1.25

                             1.25 a = 3.75 b + 5n     add this equation to the top one

2.25 a = 7.75b      divide both sides by b

2.25 a/b = 7.75    divide both sides by 2.25

a/b = 7.75/2.25 = 31/9 

A + n=4(B - n).........................(1)  

A - n =3(B +n).........................(2)

Solve these two simultaneous equations and should get:

A / B = 31 / 9 - the original ratio before they exchaned money.

sqrt (( -5- -1)^2 +  (1- - 3)^2 )

 sqrt ( 16 + 16) = sqrt 32    =   4 sqrt2

The AMOUNT of chocalate remains the same    .06 (10) = .6 l

The final mix is 10 + 50 = 60 liters     .6 liters is choc    .6 / 60 = 1%

perhaps

If three angles contain a total of 120^o and the total of all the other angles is 150^o  --  and if we are talking about

interior angles  --  the sum of the interior angles is 270^o.

This is impossible ...   

dis dude lame lmao ^

I agree with the approach of the other answer, except that there are 540^o in a pentagon.

540^o - 180^o  =  360^o

360^o / 3  =  120^o