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 #1
avatar+23254 
0

Let V be the midpoint of arc(AB) and Z the midpoint of arc(CD).

Draw VWXYZ, where W is the point of intersection with AB (W will be the midpoint of AB);

X is the point of intersection with AC;

Y is the point of intersection with CD (Y will be the midpoint of CD).

 

VWXYZ will be perpendicular to both AB and CD.

 

Since AB = 2, AW = 1 and WX = 1.

Since CD = 6, CY = 3 and XY = 3.

 

Call XW = a and call YZ = b.

 

Since WXYZ is a diameter and AB is a chord of the circle:  AW · WB  =  VW · WZ.

     --->     1 · 1  =  a · (1 + 3 + b)     --->     1  =  a · (4 + b)     --->     4a + ab  =  1     --->     ab  =  1 - 4a

 

Since WXYZ is a diameter and CD is a chord of the circle:  CY · YD  =  YZ · VY.

     --->     3 · 3  =  b · (1 + 3 + a)     --->     9  =  b · (4 + a)     --->     4b + ab  =  9     --->     ab  =  9 - 4b

 

Combining these two results:  1 - 4a  =  9 - 4b    --->     4b - 4a  =  8     --->     b - a  =  2

     --->     b  =  2 + a

 

Since     a · (4 + b)  =  1     --->     a · (4 + (2 + a) )  =  1     --->     a · (6 + a)   =  1 

                  --->     6a + a2  =  1     --->     a2 + 6a - 1  =  0

                  --->     a  =  -3 + sqrt(10)      [quadratic formula]

 

Since      b · (4 + a)  =  9     --->     b · (4 + (b - 2) )  =  9     --->     b · (2 + b)   =  9

                 --->     2b + b2  =  9     --->     b2 + 2b - 9  =  0

                 --->     b  =  -1 + sqrt(10)     [quadratic formula]

 

The diameter will be:     (a) + (1) + (3) + (b)  =  ( -3 + sqrt(10) ) + (1) + (3) + ( -1 + sqrt(10) )

                                                                      =  2sqrt(10)

 

So, the radius is:     sqrt(10)

Jun 20, 2020
 #2
avatar+866 
-1
Jun 20, 2020
 #9
avatar
-6

Oh you could do that, I mean I used to be one, then you'd be targeted by some rude Guest who subtracted a total of over 200 points from my score.

 

You should know, Hugo, I meant to do 1200 points. Your point deductions are not just for obnoxiously reprimanding the cheating AoPS posters.   Nope… there is more to it than that. You often usually post second-rate rubbish answers, thinking your lick and a prayer makes it a wondrous gift worthy of Zen contemplation. IT’S NOT! It’s worthless and irritating! Even more irritating than your griping about APoS cheats. 

 

You do not have the skills or experience to teach math in form of (worthless) hints. Even if you did have these skills, a public forum is not the place for it. It’s cumbersome and laborious –even for those to whom it is directed.  You may notice that none of the sites that teach, such as PurpleMath.com and KhanAcademy.org or sites that tutor, such as math.stackexchange and MathHelpForum.com, use that method. AoPS may use it, but only in private chats, where feedback is quick, and the hints are customized for the individual student.   

 

Other reasons for your point deductions: you post large amounts of obiter dictum and just plain bullshit, and then you inflate your score by pointing up all of your posts multiple times. You are entitled to your opinions, but why do think that you are entitled to all those points?

 

Your arrogance is magnified by the fact that you also give very few points to others.  Why are you so stingy? Are the other answers beneath you?  Maybe you just max-out your point allocation and do not have any left for anyone else. 

 

While the above is very annoying, the most irritating aspect is that you actually could present respectable answers. You actually do that occasionally, so I know you can (at least some of the time).  You really should present respectable answers more often –you could really use the practice!

 

You should also keep in mind that arrogance is a poor substitute for knowledge and practiced skill.   

Jun 20, 2020
 #1
avatar+310 
0

Hint: Try using Pick's Theorem or read the solution to a similar problem here: https://web2.0calc.com/questions/help_62291#r1

Jun 20, 2020
 #7
avatar+80 
-1
Jun 20, 2020

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